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Jet001 [13]
3 years ago
15

Here are some point to help with your difficulties Hope you have a good day :)

Mathematics
2 answers:
Arlecino [84]3 years ago
8 0

Answer:thanks

Step-by-step explanation:

pochemuha3 years ago
4 0

Answer:

your awesome

Step-by-step explanation:

Thank you

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IgorLugansk [536]

Answer:

id.k but i need points sorry

Step-by-step explanation:

5 0
3 years ago
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1. Flight 202's arrival time is normally distributed with a mean arrival time of 4:30
Bezzdna [24]

Answer:

Step-by-step explanation:

1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min

By comparing P(0 ≤ Z ≤ 30)

P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)

Using Table

P(0 ≤ Z ≤ 1) = 0.3413

P(Z > 1) = (0.5 - 0.3413) = 0.1537

∴ P(Z > 45) = 0.1537

2)  By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)

P(Z ≤ 15 - 30/15) = P(Z ≤ -1)

Using Table

P(-1 ≤ Z ≤ 0) = 0.3413

P(Z < 1) = (0.5 - 0.3413) = 0.1587

∴ P(Z < 15) = 0.1587

3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)

P(Z ≤ 60 - 30/15) = P(Z ≤ 2)

Using Table

P(0 ≤ Z ≤ 1) = 0.4772

P(Z > 1) = (0.5 - 0.4772) = 0.0228

∴ P(Z > 60) = 0.0228

6 0
3 years ago
At the fair,Kate found a strange machine with a sign on it labeled, enter a number. When she pushed the number 15, the machine d
Ivan

apparently subtracting 6

15-6=9

23-6=17

100-6=94

77-6=71

6 0
3 years ago
Pls HELP WITH THESE TWO QUESTIONS NO LINKS
Marta_Voda [28]

Answer:

The answer to the first question is B.

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