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Luba_88 [7]
3 years ago
12

Can I get a bit of help?

Mathematics
1 answer:
miskamm [114]3 years ago
5 0
The length why is 2.5
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Since the Boston marathon began in 1897, the finish time has been incrementally decreasing. The mean finish time to date is 231
morpeh [17]

Answer:

hello your question lacks the required options but i will provide a general answer to your question

answer : The mean value  and the standard deviation would allow us use a Z-score

Step-by-step explanation:

mean value = 231 minutes

standard deviation ( std ) = 40 minutes

sample size = 40

The parameters that would be applicable while use Z-score are : The given mean value and the standard deviation

This is because the value of a z-score gives us an information on how far we are from the mean score i.e. number of standard deviations

+Zscore means that the score  is above the average value

-Zscore means that the score is below the average value

7 0
3 years ago
A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6
Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

           Length of street light AB = 25 ft

           Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate (\frac{dw}{dt}) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, \frac{dx}{dt}=6 feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

\frac{x}{21}=\frac{x+y}{25}

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = \frac{4x}{21}

Now we take the derivative on both the sides,

\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}

= \frac{4}{21}\times 6

= \frac{8}{7}

≈ 1.14 ft per sec.

Since w = x + y

Therefore, \frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}

\frac{dw}{dt}=6+1.14

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

3 0
4 years ago
If 6 men can do a piece of work in 14 days, how many men are needed to do the work in 21days?
Ivenika [448]
Total work amount
6 men * 14 days
84 men days

If it is done within 21 days, need x men
84 men days = x men * 21 days
x = 84/21 men
x = 4 men
4 0
4 years ago
Britany has a bag with 2 mint sticks, 4 jelly treats, and 14 fruit tart chews. If she eats one piece every 9 minutes, what is th
zheka24 [161]
That "9 minutes" doesn't affect the outcome!

How many pieces of candy are in the bag at the beginning?  How many of those are "fruit tart chews?"  Write a fraction involving these 2 counts.  Remember that Britany immediately eats what she draws from the bag, so the 2nd time around, there are only 19 pieces, not 20.  What is the prob. that she will pick a jelly treat on her second draw?
Because these experiments are independent, you can find the joint probability by multiplying the 2 probabilities together.  Please show your work.
3 0
3 years ago
PLEASE HELP ME I REALLY NEED HELP!!!!!
salantis [7]
<h3>Answer:</h3>

A) x > 2; y < 2x

B) compare the locations of B and C to the shaded region of part A

C) plot the solution space on the graph of schools. points D and E are schools Lisa may attend

<h3>Step-by-step explanation:</h3>

<em>Coordinates and Plotting Points</em>

First of all, you must understand how to plot a point on a graph. Each set of coordinates is an ordered pair. "Pair" means there are two of them. "Ordered" means the sequence in which they appear has significance.

The first number in the pair is the x-coordinate, the distance to the <em>right</em> of the point x=0. (A negative value for this coordinate indicates the distance is to the <em>left</em>.)

The second number in the pair is the y-coordinate, the distance <em>up</em> from the point y=0. (A negative value for this coordinate indicates the distance is <em>down</em>.)

The coordinates (1, 3) for point A mean the point is plotted on the graph 1 unit to the right of x=0 and 3 units up from y=0. The other points are plotted in the same way. (See the labeled points on the attachment, and note their relationship to the horizontal (x) and vertical (y) scales.)

<em>Lines and their equations</em>

A line on a graph is the plot of all the (x, y) pairs on the graph that will satisfy a particular equation. Generally, there will be an infinite number of points—too many to list. For example, some of the points that will satisfy the equation

  y = 2x

are (x, y) = any of ... (0, 0), (0.001, 0.002), (903, 1806), (1.23, 2.46). (Note that the second number in the pair (y) is 2 times the first number (x). That's what y=2x means.) When we want to see the relationship between x-values and y-values that satisfy this equation, it is convenient to plot the line on a graph.

We talk about such lines using terms that describe the steepness of the line (its <em>slope</em>) and whether it goes up to the right (positive slope), down to the right (negative slope), or is vertical (undefined slope) or horizontal (zero slope). In Algebra, as in Geometry, knowing only 2 points is sufficient to define the line we're concerned with. One of the points commonly used to describe a line is its "y-intercept", the point where it crosses the vertical line at x=0.

<em>Inequalities</em>

For problems such as this one, it is sometimes convenient to talk about all the points that are above or below (or left or right) of a given line. The symbols >, <, ≥, and ≤ are used in place of the equal sign in the relation describing these points. A relation that uses one of these symbols instead of the equal sign is called an "inequality."

If we write y < 2x, for example, we mean all the points such that the value of y is less than two times the value of x. Above, we said the point (x, y) = (1.23, 2.46) is on the line y=2x. Now, we can add that the point (1.23, 2.00) is part of the solution to y < 2x, since 2.00 is less than 2×1.23.

Half of the x-y coordinate plane will satisfy any such inequality. We show which half that is by using shading—coloring the portion of the plane where the points meet the requirements of the inequality (are part of the solution). In the attached graph, the solution to y < 2x is colored green. The line at the boundary of that region is dashed because points on that line are <em>equal to 2x</em>. They do <em>not</em> satisfy the requirement that the points be less than 2x.

Part A

For separating a pair of points from the rest of the group, it can be useful to consider where the other points fall in relation to a line through those two points. Here, points B and C are both on the vertical line x=3, and all the other points are to the left of that line.

We also notice that nearby points A and F are on a line with slope somewhere between 1 and 3. That is, a line with slope 2 might be used to separate points A, F (and those to their upper left) from points B and C.

These observations give us ideas for inequalities we can write that separate points B and C from the rest of the group. Two of them might be ...

  • x > 2 (shaded blue)
  • y < 2x (shaded green)

While either of these alone would serve to contain only points B and C, the two of them together form a "system" of inequalities whose solution (overlapping regions) contains only points B and C—as required by the problem statement.

Part B

Points B and C can be verified as solutions by noting their position on the graph relative to the solution regions of the given inequalities.

Part C

The graph also shows a plot of the solution to the inequality y > 2x+5. This inequality also has a boundary line with a slope of 2, and it has a y-intercept of 5 (the point where it crosses the vertical line at x=0). The solution region is shaded red.

We can identify the schools Lisa may attend by their labels in the solution region of the inequality on the graph. Those schools are D and E.

6 0
3 years ago
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