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2 years ago

Which set of statements explains how to plot a point at the location

Mathematics

1 answer:

Komok [63]2 years ago

6 0

Answer:

last one or d

Step-by-step explanation:

Lets test these statements. 1 is incorrect. 2 is incorrect 3 is incorrect 4 is correct.

The answer is the last one

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What is 10√94 simplified. Its not 98 or its decimal form.

slavikrds [6]

Answer:

Step-by-step explanation:

i think 96(probably)

have a nice day

3 0

2 years ago

Express the trig ratios as fractions in simplest terms.

Neporo4naja [7]

Answer:

See below

Step-by-step explanation:

$\cos M=\frac{adjacent}{hypotenuse}=\frac{56}{70}=\frac{4}{5}\\\\\sin L=\frac{opposite}{hypotenuse}=\frac{56}{70}=\frac{4}{5}$

Hence, both ratios are equal to each other

3 0

1 year ago

The height of a certain banner is equal to one third of its length. If the banner is 5 ft tall, write the equation that can be u

pav-90 [236]

Answer:

$L=3h$

Step-by-step explanation:

Let height of a banner be $h$ , then we know that this is $\frac{1}{3}$ of the length $L$ of the banner; so we have

$h=\frac{1}{3} L$ .

Now we can rearrange this equation to solve for the length of the banner given it's height:

$L=3h$

So there we have it!

If the banner is 5 ft tall, then it's length will be:

$L=3*5=15ft$

5 0

2 years ago

Wassup brainly peeps, one thing i need for you guys is to answer this question and you can land onto the brainliest plane.

Free_Kalibri [48]

Answer:

(B) i think

Step-by-step explanation:

comment how it help

5 0

2 years ago

Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
f(x)=x+1\qquad \qquad \qquad \qquad \qquad g(x)=x+1\\\\
-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
\\\\\\
g(x)=(1)+1\implies g(x)=2
\\\\\\
f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined$

7 0

3 years ago