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3 years ago

Find the mean of the data in the pictograph below.

Mathematics

1 answer:

Irina-Kira [14]3 years ago

8 0

<u>Final Answer:</u>

mean = 4 sundaes

<u>Solution:</u>

each bowl of sundaes contains 3 sundaes.

two scoops = 4 sundae bowls
I scream = 6 sundae bowls
dream scream = 2 sundae bowls

Sundays = 4 sundae bowls

(plus 3, the number three represents how many sundae's there are in a bowl)

(divide it by 12, since there are 12 numbers in the data set)

Mean = (4 + 4 + 4 + 6 + 6 + 6 + 2 + 2 + 2 + 4 + 4 + 4) ÷ 12

= 48 ÷ 12 = 4

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What is the answer to this problem?

Nastasia [14]

Answer is c because if count the sides of how many spaces are there

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3 years ago

For what values of b the relation R:{(b^2, 5), (5b, 6)} is not a function?

xenn [34]

Answer:

B=5,0.

Step-by-step explanation:

It's not that hard. It's just that it might throw you off a bit with the R and the other things. Functions if you don't remember are where the coordinates don't have the same x and y. So since the y1 and y2 are different then to make it not a function, you have to make x1 and x2. To make it that b would have to be = to 5 and 0.

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4 years ago

Lily goes to gym once every 8 days. Ann goes once every 12 days and Taylor comes once every 16 days. This Wednesday all of them

ahrayia [7]

<h3>Answer:</h3><h3>All of them meet at the gym again after 48 days and it will be tuesday</h3>

Step-by-step explanation:

Lily goes to gym once every 8 days.

Such that she will visit on 8, 16 , 24, 32 , 40, 48th days

Ann goes once every 12 days

Such that she will visit on 12, 24, 36, 48, 60th days ....

Taylor comes once every 16 days

Such that she will visit on 16, 32, 48, 64th days....

Comparing the common days on which they will visit again after wednesday,

it will be after 48 days, (i.e) after 6 weeks and 5 days, it will be tuesday

3 0

3 years ago

Read 2 more answers

The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the

Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as $e=\frac{c}{a}$

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)$

b) Eccentricity =5

$5=\frac{c}{a} \:c=5a$

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

$If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0$

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

$a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)$