Answer:
5 units
sin(D)= 5/13
Step-by-step explanation:
i just did the question
Using factorization method;
x²+13x+40=0
x²+13+40
Find two numbers that you can add together to give the co-efficient of variable x. (I.e 13 for this question). Also, you'll find two numbers that you can multiply with each other to give you the whole number as an answer. (I.e 40 in this question). The two numbers must be the same (i.e the two numbers that will be added to give the co-efficient of x and the two numbers that will be multiplied to give the whole number must be the same two).
The two numbers are +5 and +8
The equation will therefore be = x²+5x+8x+40
You'll then factorize (I.e use a common factor of both values to bracket them)
x(x+5)+8(x+5)
(x+8)(x+5)
x is therefore (x+8=0) or (x+5=0)
x=(x=0-8) or (x=0-5)
x= -8 or x= -5
Answer:
5
Step-by-step explanation:
5*10^5=500000 and 1*10^5=100000
Answer:
y = -17.25
Step-by-step explanation:
y/23 = -3/<em>4</em>
<em>by</em><em> </em><em>cross</em><em> </em><em>multiplication</em><em> </em><em>❌</em><em> </em><em> </em><em>;</em><em>;</em><em>;</em>
<em>4</em><em>×</em><em>Y</em><em> </em><em>=</em><em> </em><em>23</em><em>×</em><em> </em><em>(</em><em>-3</em><em>)</em>
<em>4y</em><em> </em><em>=</em><em> </em><em>(</em><em>-69</em><em>)</em>
<em>y</em><em> </em><em>=</em><em> </em><em>-69</em><em>/</em><em>4</em>
<h3><em>y</em><em> </em><em>=</em><em> </em><em>-17.25</em></h3>
<h3><em>I</em><em> </em><em>hope</em><em> </em><em>that</em><em> </em><em>this</em><em> </em><em>answer</em><em> </em><em>helps</em><em> </em><em>you</em></h3>
The activation energy is the amount of energy required to initiate a certain reaction. The activation energy may considered as an "energy barrier" that has to be overcome in order for a reaction to begin. If a reaction has a lower activation energy, then it will occur more easily and at a faster rate than a reaction with a higher activation energy. Therefore, the reason that reaction 1 is faster than reaction 2 is because it has a lower activation energy than reaction 2.
