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3 years ago

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HELP!!! PLEASE HELP ME!

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Karolina [17]3 years ago

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5+2+7
Hope this helps

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Refer to the accompanying data set and construct a % confidence interval estimate of the mean pulse rate of adult females; the

ivolga24 [154]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The 95% confidence interval of mean pulse rate for adult female is $71.98 < \mu < 79.88$

The 95% confidence interval of mean pulse rate for adult male is $62.89 < \mu < 70.57$

The correct option is C

Step-by-step explanation:

Generally the sample mean for Male pulse rate is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

= > $\= x_1 = \frac{81 + 74 + \cdots + 59 }{40 }$

= > $\= x_1 = 66.73$

Generally the standard deviation for male pulse rate is mathematically represented as

$\sigma_1 = \sqrt{\frac{\sum (x - \= x)^2 }{n-1 } }$

=> $\sigma_1 = \sqrt{\frac{\sum (81 - 66.73 )^2 + (74 - 66.73 )^2+ \cdot + (59 - 66.73 )^2 }{40-1 } }$

=> $\sigma_1 = 12.24$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma_1 }{\sqrt{n} }$

=> $E = 1.96 * \frac{12.4 }{\sqrt{40} }$

=> $E =3.84$

Generally 95% confidence interval is mathematically represented as

$\= x_1 -E < \mu < \=x_1 +E$

=> $66.73 -3.84 < \mu < 66.73 +3.84$

=> $62.89 < \mu < 70.57$

Generally the sample mean for Female pulse rate is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

= > $\= x_2 = \frac{81 + 94 + \cdots + 73 }{40 }$

= > $\= x_2 = 75.93$

Generally the standard deviation for Female pulse rate is mathematically represented as

$\sigma_2 = \sqrt{\frac{\sum (x - \= x)^2 }{n-1 } }$

=> $\sigma_2 = \sqrt{\frac{\sum (81 - 66.73 )^2 + (94 - 66.73 )^2+ \cdot + (73 - 66.73 )^2 }{40 } }$

=> $\sigma_2 = 12.73$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma_2 }{\sqrt{n} }$

=> $E = 1.96 * \frac{12.73 }{\sqrt{40} }$

=> $E =3.95$

Generally 95% confidence interval is mathematically represented as

$\= x_2 -E < \mu < \=x_2 +E$

=> $75.93 -3.95 < \mu < 75.93 + 3.95$

=> $71.98 < \mu < 79.88$

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The price of a book went up from $20 to $25. By how many percent did the price increase?

pogonyaev

Answer:

20%???

Step-by-step explanation:

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Given b(x)= (-3,7), state what the coordinates of this point will be of the following transformations are effected: 2b(x)

Dennis_Churaev [7]

The point translated up 7 and left 3. This will cause the point to go from (-3,7) to (-6,14)

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3 years ago

If two chords are perpendicular to each other and one chord is bisected, what do you know about the other chord?

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The answer is the second one. "It is the diameter."

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9+3v is greater than or equal to 6

kondaur [170]

Answer:

If you take it in terms of integers,

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