HELP!!! PLEASE HELP ME!

Mathematics

1 answer:

Karolina [17]2 years ago

3 0

5+2+7
Hope this helps

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What is difference 45 and 7/15 and 37 and 1/5

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2 2/15

Step-by-step explanation:

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Determine the volume of the solid formed by rotation about the y-axis of the region bounded by the curve y=11lnx the x-axis, the

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An ammunition producer claims his best product has an average lifespan of exactly 18 years. A skeptical product evaluator asks f

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The 90% confidence interval for the true mean lifespan of this product is between 13.1 and 16.9 years.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 50 - 1 = 49

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 1.6766

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.6766\frac{8}{\sqrt{50}} = 1.9$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 15 - 1.9 = 13.1 years

The upper end of the interval is the sample mean added to M. So it is 15 + 1.9 = 16.9 years

The 90% confidence interval for the true mean lifespan of this product is between 13.1 and 16.9 years.

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2 years ago

Seema deposited $800 in a saving account earning 2.88% compounded annually. To the nearest cent, how much will she have in 16 ye

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1260.04

Step-by-step explanation:

The formula for compound interest is:

A = P(1+ $\frac{r}{n}$ $)^{nt}$ where A is the final amount, P is the initial principal balance, r is the interest rate, n is the number of times interest applied per time period and t is the number of time periods elapsed. Since the deposit was compounded annually, just like the interest, we can omit the n in the equation.