Answer:
the amount of overhead applied during the year is $2,250,000
Explanation:
The computation of the overhead applied is shown below;
= Estimated annual overhead ÷ machine hours × actual machine hours
= $2,400,000 ÷ 400,000 machine hours × 375,000 hours
= $2,250,000
hence, the amount of overhead applied during the year is $2,250,000
Answer:
Product category units cost NRV year-end inventory
Tools:
-
Hammers 120 <u>$5.50</u> $6.00 $660
- Saws 250 $10.50 <u>$9.50</u> $2,375
- Screwdrivers 350 <u>$2.50</u> $3.10 $875
Paint products:
-
1-gallon cans 550 $6.50 <u>$5.50</u> $3,025
- Paint brushes 120 <u>$4.50</u> $5.00 $540
1) carrying value of year-end inventory:
Tools:
-
Hammers $660
- Saws $2,375
- Screwdrivers $875
- sub-total $3,910
Paint products:
-
1-gallon cans $3,025
- Paint brushes $540
- sub-total $3,565
Total $7,475
2) adjustment to tools:
Dr Cost of goods sold 250
Cr Inventory: tools 250
adjustment to paint products:
Dr Cost of goods sold 550
Cr Inventory: paint products 550
or total adjustment to inventory account:
Dr Cost of goods sold 800
Cr Inventory 800
Answer:
The answer is "
".
Explanation:
Variable cost net income
Less: Fixed overhead start
Add: Fixed overhead termination
Net revenue at cost of absorption 
Answer:
A) Breach, because the latter express warranty is valid.
Explanation:
Based on the scenario being described within the question it can be said that the result would be a breach. This is mainly due to the fact that the box stated that "will protect your feet in temperatures down to 30° below zero." and this is a valid express warranty that is being marketed by the company that created the product. Therefore since the temperature did not go below 30 and Ron still suffered frostbite then he can rightfully sue.
<h2>
Answer:</h2>
x = (log₅7) - 8
<h2>
Explanation:</h2>
<em>Given;</em>
= 7
<em>Take log of both sides;</em>
log₁₀(
) = log₁₀7 -------------(ii)
<em>From the laws of logarithm remember that;</em>
logₐ xⁿ = n logₐ x
<em>Equation (ii) can then be written as;</em>
(x + 8)log₁₀5 = log₁₀7
<em>Divide both sides by log₁₀5</em>
(x + 8) =
-----------(iii)
<em>From the laws of logarithm, remember that;</em>

<em>Equation (iii) can thus be written as;</em>
(x + 8) = log₅7
x + 8 = log₅7
<em>Make x subject of the formula;</em>
x = (log₅7) - 8