Yes. Feedly will help me create an effective personal online environment. I am able to keep up with all the topics that matter to me most. Feedly is able to help me discover insightful sources from publications and blogs. Feedly is also able to uniquely offer clean, minimalist reading experience optimized for productivity.
Answer:
Maintenance
Explanation:
Maintenance
This primarily involves updating and making improvements based on user feedback, as well as resolving any defects that arise.
Answer:
B. SSD
Explanation:
VMs or virtual machines are virtually created environment for multiple operating system on a host operating system. The host operating system has an extension called Hyper-V. The hyper-V manager helps to manage the virtual machine's activities.
The VMs can hold applications in their respective containers, which requires a partition of the storage. So when more VMs are configured, more storage memory is required to store their individual data. The VMs in a computer system can share a network interface card.
The travel agents receive compensation from suppliers such as waiting time compensation, night ride compensation, and cancellation compensation.
<u>Explanation</u>:
- The travel agents from ola, uber and other companies usually receive compensation such as 10 percent commission of booking fees. Usually, if the customer cancels the ride the travel agent will receive compensation for that ride. They also receive time compensation for their work.
- For long rides, the travel agents will receive extra compensation for that. Because the distance for that ride will be long. So they will receive these types of compensations from suppliers.
Answer:
public static void removeInRange(List<Integer> list, int value, int start, int end) {
for (int i = end - 1; i >= start; i--) {
if (list.get(i) == value) {
list.remove(i);
}
}
System.out.println(list);
}
Explanation:
- Create a method named <em>removeInRange</em> that takes four parameters, a list, an integer number, a starting index and an ending index
- Inside the method, initialize a <u>for loop</u> that iterates between starting index and ending index
- If any number between these ranges is equal to the given <em>value</em>, then remove that value from the list, using <u>remove</u> method
- When the loop is done, print the new list
