Answer:
3 5 30 32
Step-by-step explanation:
The question in English is
The age of 4 members of a family adds up to 70. Mom is 6 times bigger than her son and 10 times bigger than her daughter. Dad is 2 years older than Mom. How old are each of the family members? Write the result in ascending order and separated by spaces
Let
x----> Mon's age
y----> Son's age
z----> Daughter's age
w---> Dad's age
we know that
x+y+z+w=70 -----> equation A
x=6y ----> y=x/6 -----> equation B
x=10z ----> z=x/10 -----> equation C
w=2+x -----> equation D
substitute equation B, C and D in equation A and solve for x
x+(x/6)+(x/10)+(2+x)=70
Multiply by 60 both sides
60x+10x+6x+120+60x=4,200
136x=4,200-120
x=4,080/136
x=30 years
Find the value of y
y=x/6 -----> y=30/6=5 years
Find the value of z
z=x/10 ----> z=30/10=3 years
Find the value of w
w=2+x ----> w=2+30=32 years
Write the result in ascending order and separated by spaces
3 5 30 32
so
Daughter Son Mon Dad
Answer:
5/16
Step-by-step explanation:
It's a little easier when you write the problem like this:
3 5
----- · -----
8 6
Now reduce that 3/6 to 1/2:
1 5
----- · ----- = 5/16
8 2
7^-2= 1/7^2
= 1/14
= 0.071429
