Question

Plis help me it’s for today

Answer 1

Answer:

Following are the solution to the given points:

Step-by-step explanation:

For question 1:

$\to 3^{-4}= \frac{1}{3^4}=\frac{1}{81}=0.0123456789$

For question 2:

$\to (-2)^{3}\cdot(-2)^{4}\cdot(-2)^{-1}=-8\cdot-16\cdot -\frac{1}{2}= 128\cdot -\frac{1}{2}=-64$

For question 3:

$\to 7^{-4} \div 7^{-2}= \frac{1}{7^{4}} \div \frac{1}{7^{2}}=\frac{1}{7^{4}} \times \frac{7^{2}}{1}=\frac{1}{7^{2}} =\frac{1}{49} =0.0204081633$

For question 4:

$\to [(-3)^{2}]^3= (-3)^{2\cdot 3}= (-3)^{6}=729$

For question 5:

$\to [5 \cdot (-3)]^{2}= 25 \cdot 9=225$

For question 6:

$\to [(10 \div 5)]^{3}= [(\frac{10}{5})]^{3}=[2]^{3}=8$

For question 7:

$\to 10^6 \cdot 10^{-4} \cdot 10^2= 10^6 \cdot \frac{1}{10^{4}} \cdot 10^2= 10^2 \cdot 10^2=10^4=10,000$

For question 8:

$\to (-4)^{-5}=\frac{1}{(-4)^{5}}=- \frac{1}{1,024}=-0.0009765625$

For question 9:

$\to \frac{2^3}{2^4}= \frac{8}{16}=\frac{1}{2}=0.5$

For question 10:

$\to (-6)^3 \cdot (-6)^5 \cdot (-6)^{-5}= (-6)^3 \cdot (-6)^5 \cdot \frac{1}{(-6)^{5}}= (-6)^3 =-216$