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USPshnik [31]
3 years ago
11

8. Which diagram correctly depicts the expression below? -5 - 2 F. G. -6 -4 -2 2 4 -12 -10 -8 -6 -2 0 H. J. -8 -6 -4 -2 0 2 4 -2

4 6​
Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0

Answer:

the sender is 23 I don't no if I am right tho

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Given sin thata = 2/5 and 0° < thata < 90°. find sin 2 thata​
Andrej [43]

Recall the double angle identity:

\sin2\theta=2\sin\theta\cos\theta

With \theta measuring between 0º and 90º, we know \cos\theta>0. So from the Pythagorean identity, we get

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\dfrac{\sqrt{21}}5

Then

\sin2\theta=2\dfrac25\dfrac{\sqrt{21}}5=\dfrac{4\sqrt{21}}{25}

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4 years ago
The formula for surface area of a cube is SA = 652, where SA is the surface area and s is the
Aliun [14]

Answer:

24p^2q^2?

Step-by-step explanation:

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2 years ago
What’s measure of angle C?
Oduvanchick [21]
The angle is 60° because
B is a right angle and that adds to 90°, so dividing 90 by 3 would get 30

30 x 2 = 60

and to check the answer

x = 30

A=30
B=90
C=60

this adds to 180 which is correct because the angles in a triangle add to 180° :)
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4 years ago
Monica's school band held a car wash to raise money for
Ksivusya [100]

Answer:

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Step-by-step explanation:

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3 years ago
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
3 years ago
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