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3 years ago

Answer the statistical measures and create a box and whiskers plot for the following set of data.

Mathematics

1 answer:

iren [92.7K]3 years ago

8 0

Answer:

Min:2

Q1:5

Med:7

Q3:13

Max:15

Step-by-step explanation:

Hope the picture helps. Not the best at drawing haha

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Bruce flipped a penny 5 times. It landed on heads 2 times and tails 3 times. If he flips the coin a 6th time, which of the follo

Brums [2.3K]

Answer:

Step-by-step explanation:

because if the pattern were 2 on heads and three on tails the next flip would be heads

5 0

3 years ago

A football coach walks 12 meters westward, then 16 meters eastward,

tino4ka555 [31]

Answer:

Total distance traveled = 56 m

Total displacement is 12 m

Direction of coach is westward

Step-by-step explanation:

It is given that football coach first go 12 meter westward then 16 meter eastward.

So no position of coach in eastward direction = 16 - 12 = 4 m

And then 22 m west westward

Therefore position of coach now is 22-4 = 18 m westward

And finally 6 m eastward

Therefore final position of coach is 18-6= 12 m westward

So displacement of coach is 12 m and direction is westward.

Total distance traveled = 12+16+22+6= 56 m

4 0

3 years ago

Read 2 more answers

) Find the coordinates of the point A' which is the symmetric point

soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

$\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1$

x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

7 0

3 years ago

Simply<br> 7p2 x 3p<br> 14p4

vivado [14]

Answer:

${ \tt{ = \frac{7 {p}^{2} \times 3p}{14 {p}^{4} } }} \\ = { \tt{ \frac{21 {p}^{3} }{14 {p}^{4} } }} \\ = { \tt{1.5 {p}^{ - 1} }}$

6 0

3 years ago

What else would need to be congruent to show that ABC = PQR by sss

Katen [24]

Ab=pq
qr= bc
and so on

7 0

3 years ago