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ANEK [815]
3 years ago
14

Helppp please!!!!!!!!!!!

Mathematics
1 answer:
marusya05 [52]3 years ago
4 0

Answer:

C.

Step-by-step explanation:

If y=-3, then you substitute -3 into the equation every place that there is y, making it 4+(-3)/4(-3). This simplifies into 4-3/-12 which is 1/-12 or -1/12

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Write an expression to represent susans age in three years when a represents her present age.
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Well, since a is Susan’s current age, we would add three to a to get her age in three years
So our expression would be:
a + 3
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Look at this graph:
vladimir2022 [97]

Answer:

2

Step-by-step explanation:

slope=rise/run=20/10=2/1=2.

6 0
3 years ago
let a,b,c,d be four integers (not necessarily distinct) in the set {1,2,3,4,5}. the no. of polynomials x^4+ax^3+bx^2+cx+d which
Eddi Din [679]
By either long or synthetic division, it's easy to show that

\dfrac{x^4+ax^3+bx^2+cx+d}{x+1}=x^3+(a-1)x^2+(-a+b+1)x+(a-b+c-1)-\dfrac{a-b+c-d-1}{x+1}

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I'm not sure how to count the number of solutions (software tells me it should be 80), but hopefully this is a helpful push in the right direction.
8 0
3 years ago
what does this mean? Could I be lectured on this? will give 50 points and brainliest to the fastest responder
KiRa [710]

Answer:

Nonproportional

Step-by-step explanation:

A line that is proportional will always pass through the origin (0, 0). If it does pass through the origin, then x and y have a proportional relationship.

Best of Luck!

7 0
3 years ago
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An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click
Sergeeva-Olga [200]

Answer:

A.    \mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}

B.    \mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }

Step-by-step explanation:

Given that:

An investment of  Amount = $8000

earns  at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A)  Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

A = Pe^{rt}

where;

A = (8000) \ e ^{0.7t}

The instantaneous rate of change = \dfrac{dA}{dt}

\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )

= 8000 \dfrac{d}{dt}e^{0.07 \ t}

\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}

\dfrac{dA}{dt}= 560 e^{0.07 \ t}

At t = 2 years; the instantaneous rate of change is:

\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}

\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

12000 = (8000)e^{0.07 \ t}

\dfrac{12000 }{8000}= e^{0.07 \ t}

1.5= e^{0.07 \ t}

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

\dfrac{dA}{dt}= 560 e^{0.07 \ t}

At t = 5.79

\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}

\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }

7 0
3 years ago
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