Answer:
composite functions are
![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)

Step-by-step explanation:
We are given
![f(x)=\sqrt[3]{x^2+2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%5E2%2B2%7D)
Since, f(x) is composite function

Let's assume

we can replace x^2+2 as g(x)
![f(g(x)))=\sqrt[3]{g(x)}](https://tex.z-dn.net/?f=f%28g%28x%29%29%29%3D%5Csqrt%5B3%5D%7Bg%28x%29%7D)
now, we can replace g(x) as x
![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
so, composite functions are
![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)

I think the equation might be -5+8 ????
idrk
Answer:
126
Step-by-step explanation:
52 * 3 = 126
Answer:
hope this helps you.........
First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.