X^2+7x-8>0 eliminating denominator
Factoring (x+8)(x-1) must be positive so
Case 1 both positive is x>-8 and x>1. For both to occur x>1
Case 2 both are negative (x+8)<0 and (x-1)<0 so x<-8 and x<1. For both to occur x<-8
Therefore x<-8 or x>1
Since area= length•width, for this u would have to divide the area by the width to get the length, i hope this helps
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