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3 years ago

Help please I’m trying to get my grade up cause my mom is gonna check my grades and she is gonna be mad!!!

Mathematics

1 answer:

muminat3 years ago

3 0

Answer:

lol dude, multipy all angles of the tryangle

Step-by-step explanation:

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What is the expanded form of 3x(x+3)^2=?

il63 [147K]

3x(x+3)^2
3x(x^2 + 6x + 9)
= 3x^3 + 18x^2 + 27x

answer
3x^3 + 18x^2 + 27x

8 0

3 years ago

What is the sum of sqrt -2 and sqrt -18

Assoli18 [71]

Answer:

4i sqrt(2)

Step-by-step explanation:

sqrt(-2) + sqrt(-18)

We know sqrt(ab)= sqrt(a) sqrt(b)

sqrt(-1)sqrt(2) + sqrt(9) sqrt(-2)

sqrt(-1)sqrt(2) + sqrt(9) sqrt(2)sqrt(1)

We know the sqrt(-1) is equal to i

i sqrt(2) +3 sqrt(2) i

i sqrt(2) +3i sqrt(2)

4i sqrt(2)

3 0

3 years ago

Find (a) the value of q in radians (b) the area of the shaded region in cm²

Tresset [83]

Answer:

(a) 1.18

(b) 99.71

Step-by-step explanation:

to know the value of q in degrees we can use cosine of q

$\cos (q) = \frac{OR}{OQ}\\\\\cos (q) = \frac{5}{13}\\\\q = \cos^{-1}(\frac{5}{13})\\\\q \approx 67.38$

now to radians

the formula is

$x\times\frac{2\pi}{360}\\\\$

with x the degrees

$67.38\times \frac{2\pi}{360}\\\\=\frac{67.38\pi}{180}\\\\\approx 0.374\pi\\\\\approx 1.18$

so the measure of angle q is 1.18 radians

so now for part b

$A = \frac{r^2 \alpha }{2}\\\\$

with $\alpha$ being the central angle in radians

for degrees is the following

$A = \frac{\theta}{360}\times \pi r^2$

so we have

$A = \frac{13^2 (1.18)}{2}\\\\A = 99.71$ cm^2

4 0

3 years ago

Pls help being timed

kotykmax [81]

I did the equation, however as for my final answer, i got 13/105 but the fraction doesn't match with any of the choices...

6 0

3 years ago

Read 2 more answers

LAST ONE Find the range of the data. 16, 55, 61, 92, 31 range =

agasfer [191]

Answer:

Step-by-step explanation:

arrange the data set from least to greatest:

16, 31, 55, 61, 92

Range = Highest value - Lowest value = answer

Range = 92 - 16 = 76

4 0

3 years ago