Answer:
We have only 3 B available, and as per the requirement. we need to provide each of them with 1st preference. However, five students have the first preference as B, and we have only 3 B available. Thus, the dream of providing each of them with first preference job seems to be impossible, as we are 2 short of what is required, and that is 5. No combination is possible hence.
Explanation:
Remember we have 9 students, but we have only 3 B available and we have five students with B as first preference. Hence, we are 2 less than the number of B required. No way hence we can provide all the students the job, which is their first preference.
Answer:
Replace the comment with:
int p = 1; p < data.length - 1; p++
Explanation:
See attachment for proper format of the code
The loop header is expected to test if the current element is greater than the adjacent elements (i.e. array elements before and after it)
It should be noted that the first element of the array (index 0) has not element before it and the last element of the array has no element after it.
So, the loop header must start from index 1 and end at the last index - 1
The option that illustrates this is:
int p = 1; p < data.length - 1; p++
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Explanation:
i took the test
I don't think so becase some games are offline. So I think the answer is no!
Answer:Denier is a unit of measurement that is used to determine the fiber thickness of individual threads or filaments used in the creation of textiles and fabrics. Fabrics with a high denier count tend to be thick, sturdy, and durable. Fabrics with a low denier count tend to be sheer, soft, and silky.
Explanation:
idk if this is right.
