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3 years ago

Plz help will mark brainliest

Mathematics

1 answer:

Leni [432]3 years ago

7 0

Answer:

∠ A = 82°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

A is an exterior angle of the triangle, then

∠ A = 49° + 33° = 82°

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X2 – 7x + 6 = -8<br> solve using factoring

murzikaleks [220]

Answer:

Step-by-step explanation:

Rewrite this in standard quadratic equation form: x^2 - 7x + 6 + 8 = 0, or x^2 - 7x + 14 = 0. This does not factor easily, so I will use the quadratic formula to find the roots and then write out the factors based upon the roots:

The discriminant is b^2 - 4ac, which here is (-7)^2 - 4(1)(14) = -7.

Because the discriminant is negative, we know that there are two unequal, complex roots. They are:

-(-7) ± i√7 7 ± i√7

x = ----------------- = ---------------

2 2

One factor is (x - [1/2]{7 ± √7} )

7 0

2 years ago

Someone pls help me!!

steposvetlana [31]

Answer:

$r = \frac{12\sin 20\degree}{ \sin 35\degree }$

Step-by-step explanation:

By sine rule

$\frac{r}{ \sin \angle R } = \frac{p}{ \sin \angle P} \\ \\ \frac{r}{ \sin 20\degree } = \frac{12}{ \sin 35\degree } \\ \\ r = \frac{12\sin 20\degree}{ \sin 35\degree }$

5 0

3 years ago

Which statements are true about the trigonometric ratios of this triangle

rosijanka [135]

Answer:

Options (1), (2), (3) and (4)

Step-by-step explanation:

By applying the sine and cosine rules in the given triangle,

sinθ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

cosθ = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

cos(30°) = $\frac{AC}{AB}$

= $\frac{11\sqrt{3} }{22}$

= $\frac{\sqrt{3}}{2}$

sin(30°) = $\frac{BC}{AB}$

= $\frac{11}{22}$

= $\frac{1}{2}$

cos(60°) = $\frac{BC}{AB}$

= $\frac{11}{22}$

= $\frac{1}{2}$

sin(60°) = = $\frac{AC}{AB}$

= $\frac{11\sqrt{3} }{22}$

= $\frac{\sqrt{3}}{2}$

Options (1), (2), (3) and (4) are the correct options.

3 0

2 years ago

Which function has the same y-intercept as the one below

Over [174]

Check the picture below, so let's check the equations below hmmm

$\boxed{A}\\\\ y=\cfrac{16-3x}{4}\implies y=\cfrac{-3x+16}{4}\implies y = \cfrac{-3x}{4}+\cfrac{16}{4}\implies y=-\cfrac{3}{4}x\stackrel{\stackrel{b}{\downarrow }}{+4}~\hfill \bigotimes \\\\[-0.35em] ~\dotfill$

$\boxed{D}\\\\ y+4=2x\implies y=2x\underset{\stackrel{\uparrow }{b}}{-4}\qquad \textit{\Large \checkmark}\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

5 0

1 year ago

The function ƒ(x) = −(x + 3)^2 − 4 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an

Nookie1986 [14]

Answer:

Step-by-step explanation:

The second one I believe.

3 0

2 years ago