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denis23 [38]
3 years ago
12

What is 4km:370m in simplest form

Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0

Answer:

4.37 KM

Step-by-step explanation:

370 m to KM = 0.37 KM

then you sum 4 KM + 0.37 KM and you have 4.37 KM in its simplest form.

Best regards

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write an expression for add 2 and 4 and multiply the sum by 3 next add 5 to that product in double the results
Rzqust [24]
So let's start from the beginning.

Add 2 and 4:

(2 + 4)

Multiply the sum by 3:

3(2 + 4)

Then add 5 to that product:

3(2 + 4) + 5

Then double the results:

2[3(2 + 4) + 5]
8 0
3 years ago
Find e^cos(2+3i) as a complex number expressed in Cartesian form.
ozzi

Answer:

The complex number e^{\cos(2+31)} = \exp(\cos(2+3i)) has Cartesian form

\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2).

Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}.

Then,

\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}. (I)

Now, recall the definition of the complex exponential:

e^{z}=e^{x+iy} = e^x(\cos y +i\sin y).

So,

e^{2i-3} = e^{-3}(\cos 2+i\sin 2)

e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

Thus,

e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)

Now we group conveniently in the above expression:

e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2.

Now, substituting this equality in (I) we get

\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2.

Thus,

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

5 0
3 years ago
Karin predicts that she will spend 48 minutes biking and 24 minutes running p. What is the total distance of the race
Digiron [165]
72 all you have to do is add the 2 times.
5 0
3 years ago
Read 2 more answers
Write an equation for the line that passes through (- 3, 5) and is parallel to y = - 6x + 1.
soldier1979 [14.2K]

Answer:

y-5 = -6(x+3) OR y = -6x-13

Step-by-step explanation:

Let's use slope-intercept form to solve this problem.

Slope intercept form is the following:

y-y1 = m(x-x1)

x1 and y1 are given by the point in the problem.

x1 = -3, y1 = 5.

m is given by the equation in the problem. Lines that are parallel have the same slope. Thus,

m = -6.

If we plug these values into the equation for slope intercept form, we get the following:

y-5 = -6(x-(-3)) which becomes y-5 = -6(x+3)

This is an acceptable answer to the problem. However, point-slope form is also a way it can be written.

y-5 = -6x-18

y = -6x-13

3 0
2 years ago
If (2⁶)×=1, what is the value of x?
marissa [1.9K]

Answer:

Step-by-step explanation:

(2⁶)ˣ = 1

2⁶ˣ = 1

6x = 0

x = 0

3 0
3 years ago
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