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Nesterboy [21]
3 years ago
12

Please help ! It's timed!

Mathematics
1 answer:
Sphinxa [80]3 years ago
8 0

Answer:

The answer to your first question is A You can find slope through the equation Change in Y over change in x. and find the y intercept by using the growth rate and multiplying or dividing it by the x coordinate until the Y value hits 0,  

Step-by-step explanation: If you dont feel like doing the work copy and paste the equations into desmos graphing calculator and it will tell you everything

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X+2<br> X-2<br> 2x+y<br> x + 1<br> what’s the answer
icang [17]

Answer:

( 3x - 2, 2x ± yx ) ± 1

Step-by-step explanation:

5 0
3 years ago
RATHER THAN USE DECIMALS-convert it to cents..
stepan [7]

Answer:

<h2>there are 22 dimes</h2><h2>there are 44 nickles</h2><h2 />

Step-by-step explanation:

D be dimes and N be nickles

2 nickles as dime

nickle = 5 cents and dime =10 cents

N=2D

0.10 D + 0.05 (N)=4.4 substitute N=2D

0.10 D +0.05(2D)=4.4

0.10D+0.10D=4.4

0.20 D=4.4

D=4.4/0.2 = 22

<h2>there are 22 dimes</h2>

N=2D

N=2(22)

N=44

<h2>there are 44 nickles</h2>

check : 0.10(22)+0.05(44)= 4.4 (correct)

5 0
3 years ago
Melissa’s birthday is next week and she has been receiving cards in the mail with different amounts of money. She has received 5
hoa [83]
Adding another card with value $25 would decrease the standard deviation because it is closer to the mean the the current standard deviation.
3 0
3 years ago
Read 2 more answers
Right and solve a proportion to answer the question 3/4 is 75% of what number
ra1l [238]

Answer: 1

Step-by-step explanation:

Let the number be p

75% of P= 3/4

75/100 of P = 3/4

0.75P =3/4

Cross multiply

0.75p×4=3

0.3p=3

P=3/0.3

P= 1

Therefore 75% of 1 = 3/4

7 0
3 years ago
A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover
riadik2000 [5.3K]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

\left[\begin{array}{cccc}T&H&S&P\\S&600&1300&2000\\L&400&300&400\end{array}\right] = A.

In the above matrix A, the columns refers the three type of books and the rows refers the from which stores the books are been sold.

The numbers represents the corresponding sales in the month of January.

The sale is same for the 6 months.

Hence, 6A = \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right]. This matrix 6A represents the total sales over the 6 months.

(b)

If we denote the books in stock at the starting of January by B, then

B = \left[\begin{array}{cccc}T&H&S&P\\S&1000&3000&6000\\L&1000&6000&3000\end{array}\right].

Each month, the chain restocked the stores from its warehouse by shipping 500 hardcover, 1,400 softcover, and 1,400 plastic books to San Francisco and 500 hardcover, 500 softcover, and 500 plastic books to Los Angeles.

If we represent the amount restocked books at the end of each month by another matrix C, then

C = \left[\begin{array}{cccc}T&H&S&P\\S&500&1400&1400\\L&500&500&500\end{array}\right].

This restocking will be done for 5 times before the end of June.

If there would be no sale, then the stock would be

B + 5C = \left[\begin{array}{cccc}T&H&S&P\\S&1000+2500&3000+7000&6000+7000\\L&1000+2500&6000+2500&3000+2500\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right].

Since, the total sale is given by 6A, at the end of June, the inventory in each store can be shown as following,

B+5C-6A \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right] - \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&-100&2200&1000\\L&1100&6700&3100\end{array}\right]

6 0
3 years ago
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