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3 years ago

Dont answer this question if you dont know the answer

Mathematics

1 answer:

nekit [7.7K]3 years ago

3 0

Answer:

Step-by-step explanation:

sin = 5/13

cos = 12/13

tan = 5/12

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The sum of two rational numbers is -2. If one of the numbers is -14/5, find the other.

Marat540 [252]

Answer:

$\frac{4}{5}$

Step-by-step explanation:

$\frac{ - 14}{5} + x = - 2 \\ x = - 2 + \frac{14}{5 } \\ x = \frac{ - 10 + 14}{5} \\ \: x = \frac{4}{5} \\ therefore \: the \: other \: number \: is \: \frac{4}{5}$

7 0

3 years ago

Read 2 more answers

BOIS

sineoko [7]

The event will have 27 tables, with 2 adults and 3 children in each table.

Step-by-step explanation:

The greatest number of tables the planner can set up is determined by finding the greatest common factor in 54 and 81. This is given by;

54 81----------------divided by 3

3 18 27---------------divided by 3

3 6 9---------------divided by 3

3 2 3---------------no common divisor

The greatest number of table will be given by : 3×3×3=27

The number of adults in each table will be 2

The number of children in each table will be 3

Learn More

Greatest common factor : brainly.com/question/13133626

Keyword : greatest number

#LearnwithBrainly

4 0

3 years ago

What's 1.25 times 12

Juli2301 [7.4K]

The awnser is 15
hope that was helpful

7 0

4 years ago

Read 2 more answers

At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

$P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%$

Hence, a) 4.6798, and b) 19.8%.

7 0

3 years ago

The National Safe Kids Campaign and Bell Sports sponsored a study that surveyed 8,159 children ages 5 to 14 who were riding bicy

Nuetrik [128]

8159 divided by five times two then, divide that by twenty and multiply by 13, The answer is about 2611 kids wore helmets properly while riding bike

8 0

3 years ago