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timurjin [86]
3 years ago
11

the distance between two cities is 1440 miles is time rides his bike 9.6 miles per day how many days will it take for him to tra

vel this distance​
Mathematics
2 answers:
GenaCL600 [577]3 years ago
6 0

Answer:

150

Step-by-step explanation:

elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

150

Step-by-step explanation:

You would divide the distance (1440) by how much he would go each day (9.6) and the answer is the amount of days

1440÷9.6=150

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Which of the following are the coordinates of the vertex of Y=3x2 + 3?
Lemur [1.5K]

Answer:

(0,3)

Step-by-step explanation:

y = 3x^2 +3

This is in the form

y = a(x-h)^2 +k

Where the vertex is (h,k)

y = 3(x-0)^2 +3

The vertex is (0,3)

6 0
4 years ago
Can someoneplzzz do this???<br> Domain:<br> Range
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Greetings! Hope this helps!

Answer

D {-3, 5}

R: {0,4}

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3 0
3 years ago
A researcher wishes to estimate the percentage of adults who support abolishing the penny. What size sample should be obtained i
alex41 [277]

Answer:

sample size if he uses a previous estimate of 32​% is 523

sample size if he does not use any prior​ estimates is 601

Step-by-step explanation:

estimate E = 4 percentage = 0.04

confidence Cl = 95% = 0.95

previous estimate p = 32% = 0.32

q = 1 - 0.32 = 0.68

to find out

size of sample

solution

first we calculate z value for 95% confidence E = 0.04 is 1.96

from probability P(-1.96 < z < 1.96) = 0.95)

here z = 1.96

so in 1st part size of sample we know

E = z × \sqrt{pq/n}

put all value E, z p and q and we get n

n = (z/E)² ×p×q

n = (1.96/0.04)² ×0.32×0.68

n = 523

sample size if he uses a previous estimate of 32​% is 523

now in 2nd part we take p = 0.5

so n will be

n = (z/E)² ×p×q

n = (1.96/0.04)² ×0.5×0.5

n = 601

sample size if he does not use any prior​ estimates is 601

6 0
4 years ago
Does the order matter when rotating an image?
xz_007 [3.2K]

Answer:

the order is important when you are performing a composite transformation

4 0
3 years ago
2. A square-based tent has the cross-sectional
ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m

In ΔBGD,

sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

                                  = 1 m + 1.732 m

                                  = 2.732 m

(b)

DF = ?

In ΔAOB,

tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\

According to the figure, OB = GE = 1.733 m

In ΔBGD,

tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m

According to the figure, DE = DG + GE

                                      DE = 1 m + 1.733 m

                                     DE = 2.733 m

Length of the base, DF = 2 X DE

                              DF = 2 X 2.733 m

                               DF = 5.466 m

8 0
3 years ago
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