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Marysya12 [62]
2 years ago
6

13. The initial value of a particular vehicle is $20,000. After one year, the vehicle is worth $17,000. If the

Mathematics
1 answer:
Dima020 [189]2 years ago
7 0
I think it would be D that’s what I think
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Which of the following fractions can be represented by a terminating decimal? OA 8/9 OB)13/8 OC) 4/3 OD) 6/11​
velikii [3]

Answer:

\frac{13}{8}

Step-by-step explanation:

\frac{13}{8}   \:  \: cuz \: when \: u \: simplify \: into \: a \: decimal \: would \: be \: 1.625 \\ and \: if \: u \: round \: would \: be \: 2 \: so \: u \: take \: out \: the \: decimal \:

6 0
3 years ago
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The circular opening of a tunnel has a circumference of 36 meters. What is the diameter of the tunnel?
Elza [17]
C=2(3.14159...)R
You’re given the circumference, so all you need to do is plug that in and simplify.
36=2(3.14159...)R
36=6.28R
36/6.28=R
R is about 5.73
7 0
3 years ago
35 POINTS HELP ASAP!!!
Allisa [31]

Answer: 3

Step-by-step explanation:

3:1

\frac{3}{1}=3

6 0
3 years ago
Jonna is 4 years older than her brother which of the following expression shows the sum of their ages if B represents Jonas brot
Svet_ta [14]
If B is Jonas and his sister is 4 years older, that would be 4 plus B
4 0
3 years ago
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Which of the following is a like radical to RootIndex 3 StartRoot 7x EndRoot?
lana [24]

Answer:

A. 4 (RootIndex 3 StartRoot 7 x EndRoot)  or 4(\sqrt[3]{7x})

Step-by-step explanation:

Given:

A radical whose value is, r_1=\sqrt[3]{7x}

Now, we need to find the like radical for r_1.

Let the like radical be r_2.

As per the definition of like radicals, like radicals are those that can be expressed as multiples of each other.

So, if two radicals r_1\ and\ r_2 are like radicals, then

r_1 = n \times r_2


Where, 'n' is a real number.

Here, r_1=\sqrt[3]{7x}

Now, let us check all the options .

Option A:

4 (RootIndex 3 StartRoot 7 x EndRoot) or r_2=4\sqrt[3]{7x}

Now, we observe that r_2 is a multiple of r_1 because

r_2=4\times \sqrt[3]{7x}\\\\ r_2=4\times r_1..............(r_1=\sqrt[3]{7x})

Therefore, option A is correct.

Option B:

StartRoot 7 x EndRoot or r_2=\sqrt{7x}

As the above radical is square root and not a cubic root, this option is incorrect.

Option C:

x (RootIndex 3 StartRoot 7 EndRoot) or r_2=x\sqrt[3]{7}

As the term inside the cubic root is not same as that of r_1, this option is also incorrect.

Option D:

7 StartRoot x EndRoot or r_2=7\sqrt{x}

As the above radical is square root and not a cubic root, this option is incorrect.

Therefore, the like radical is option (A) only.

4 0
3 years ago
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