The range of the function is: ![\{y | y \ge -2 \}](https://tex.z-dn.net/?f=%5C%7By%20%7C%20y%20%5Cge%20-2%20%5C%7D)
<h3>What is the range of a function?</h3>
The range of a function is the set of output values the function can take
The function is given as:
![g(x) = |x - 12| -2](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%7Cx%20-%2012%7C%20-2)
The above function is an absolute value function;
And it is represented as:
![g(x) = a|x - h| + b](https://tex.z-dn.net/?f=g%28x%29%20%3D%20a%7Cx%20-%20h%7C%20%2B%20b)
When a is positive, then the range of the function is:
![y \ge b](https://tex.z-dn.net/?f=y%20%5Cge%20b)
By comparison, we have:
![a =1](https://tex.z-dn.net/?f=a%20%3D1)
![b = -2](https://tex.z-dn.net/?f=b%20%3D%20-2)
Hence, the range of the function is: ![\{y | y \ge -2 \}](https://tex.z-dn.net/?f=%5C%7By%20%7C%20y%20%5Cge%20-2%20%5C%7D)
Read more about range at:
brainly.com/question/6615538
It will be opened about 1,080 times in april because there are 30 days in april. All you need to do is multiply 36 x 30 and you get 1,080
Answer:
If you ever need help on a question and you don’t know the answer just remember this quote “ purple is always the answer”.
Step-by-step explanation: Hope this helps u!
Density = m/v with mass being in grams and volume in mL......
192 grams/250 mL = 0.768 g/mL
Answer:
Pick up point is 1.43 km from the school and drop point is 3.57 km from the school ( to the nearest hundredth).
Step-by-step explanation:
School <----------- 5 km ---------------> Home
_______ P _______ D _______
x km y km 5-x-y km
_______
y
_________________
5-x km
D is the point where Peter drops off N and P is the pick point x km from the school where Peter picks up R. He travels back y km to pick up R.
We work in times:
Time = distance / speed
The time that R walks from the school to point P is the same as Peter travels the distance (x + 2y) km, so we have
x/5 = (x + 2y)/20
20x = 5x + 10y
15x - 10y = 0 A
The time that N walks home equals the time that Peter travels y + 5 - x km.
So (y + 5 - x)/20 = (5 - x - y)/5
5y + 25 - 5x = 100 - 20x - 20y
15x + 25y = 75
3x + 5y = 15 B
Solving equation A and B
15x - 10y = 0
3x + 5y = 15
Multiply the second equation by 2:
6x + 10y = 30
Adding this to the first equation
21x = 30
x = 30/21 = 1.4285
So 3(1.4285) + 5y = 15
y = 2.1428
Pick up x = 1.43 km
and the drop is 1.43 + 2.14 = 3,57 km from the school