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laiz [17]
3 years ago
9

When performing a multiplication or division calculation, significant figures in the calculated result are dictated by the _____

___of the measured numbers. The calculated result should have ________the measured number in the calculation with the fewest _______.
Chemistry
1 answer:
Contact [7]3 years ago
3 0

Answer:

Explanation:

When performing a multiplication or division calculation, significant figures in the calculated result are dictated by the <u>significant figures</u> of the measured numbers. The calculated result should have <u>the same significant figure as</u> the measured number in the calculation with the fewest <u>significant figures</u>.

<em>According to the rule guiding significant figures during mathematical operations; when performing multiplications or divisions involving multiple numbers, the final answer should have the same significant figures as the number with the least significant figures.</em>

For example: if 10.54 and 101.25 are multiplied, the final answer should have the same significant figure as 10.54 because this is the number with the least significant figure among the numbers involved in the entire operation.

10.54 has 4 significant figures while 101.25 has 5 significant figures. The final answer should, therefore, have 4 significant figures.

Thus; 10.54 x 101.25 = 1,067

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According to the kinetic theory, what is the kinetic energy of a gas molecule proportional to? volume of the gas pressure of the
Hatshy [7]

ANSWER: C temperature of the gas

5 0
4 years ago
The coldest temperature ever recorded on Earth was -128.6°F (recorded at Vostok Station, Antarctica, on July 21, 1983). Express
Sever21 [200]

Answer : The correct option is, -89.2^oF\text{ and }183.9K

Explanation :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=(^oF-32)\times \frac{5}{9}

where,

^oF = temperature in Fahrenheit

^oC = temperature in centigrade

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273.15+^oC

where,

K = temperature in Kelvin

^oC = temperature in centigrade

As we are given the temperature in Fahrenheit is, -10

Now we have to determine the temperature in degree Celsius.

^oC=(^oF-32)\times \frac{5}{9}

^oC=(-128.6^oF-32)\times \frac{5}{9}

^oC=-89.2

Now we have to determine the temperature in Kelvin.

K=273.15+^oC

K=273.15+(-89.2^oC)

K=183.9

Therefore, the temperature in degree Celsius and Kelvin are, -89.2^oF\text{ and }183.9K

7 0
3 years ago
Please explain the relationship between the terms: <br> Element, atom, molecule, and compound.
umka2103 [35]
An element is made up of an atom, a molecule is a bunch of elements, and a comping is a bunch of molecules
4 0
3 years ago
Write the net ionic equation for this precipitation reaction. Include physical states. ( NH 4 ) 2 CO 3 ( aq ) + Ca ( ClO 4 ) 2 (
Bad White [126]

Answer:

The net ionic equation:

Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)

Explanation:

The given chemical reaction is as follows.

(NH_{4})_{2}CO_{3}(aq)+Ca(ClO_{4})_{2}(aq) \rightarrow CaCO_{3}(s)+2NH_{4}ClO_{4}(aq)

The total ionic equation is as follows.

2NH_{4}^{+}(aq)+ CO_{3}^{2-}(aq)+Ca^{2+}(aq)+2ClO_{4}^{-}(aq) \rightarrow CaCO_{3}(s)+2NH_{4}^{+}(aq)+2ClO_{4}^{-}

Similar ions on the both sides of the reaction will be cancelled.

The remaining reaction is

Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)

Therefore, the net ionic reaction is as follows.

Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)

8 0
4 years ago
Combustion of 25.0 g of a hydrocarbon produces 86.5 g of co2. what is the empirical formula of the compound?
Step2247 [10]
Combustion is a reaction between a combustible substance and oxygen, to ultimately produce carbon dioxide and water. Reaction between carbon and oxygen would give,

                               C     +     O2      ------>  CO2

Here, we have 86.5 grams of carbon dioxide, CO2, which is a product of combustion. Dividing this mass by the molar mass of CO2, which is 44 grams, we can determine the number of moles of CO2. 

                          <u>     86.5 g CO       </u>   = 1.966 moles CO2
                            44 g CO2/ mole

Considering that CO2 is composed of 1 mole of carbon and 2 moles of oxygen, and that with complete combustion, 1 mole of carbon reacts to produces 1 mole of CO2, we can then determine the mass of the carbon in the hydrocarbon fuel. 

        1.966 moles CO2   x   <u>   1 mole C   </u>    x   <u>   </u><u>12 g C   </u>  = 23.59 g C
                                             1 mole CO2          1 mole C

We were given 25.0 grams of the fuel hydrocarbon. A hydrocarbon is a substance consisting of carbon and hydrogen. To determine the mass of the hydrogen in the fuel, we simply subtract 23.59 grams from 25.0 grams. 


            25.0 g - 23.59 g = 1.41 grams Hydrogen 

To know the number of moles of hydrogen, we divide the mass of the hydrogen in the fuel by the molar mass of hydrogen, which is 1.01 g/mole. Thus, we have 1.396 mole hydrogen. 

To determine the empirical formula, we divide the number of moles carbon by the number of moles hydrogen, and find a factor that would give whole number ratios for the carbon and hydrogen in the fuel, 

Carbon:     <u>  1.966 mol   </u>   = 1.408   x   5 (factor)     = 7
                    1.396 mol

Hydrogen:  <u>  1.396 mol   </u>    = 1.00   x    5 (factor)    = 5
                     1.396 mol

Thus, the empirical formula is C7H5

       
4 0
4 years ago
Read 2 more answers
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