You can't divide by 0. It is impossible.
Answer:
Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.
Exact Form:
x = − 70 ± √4210/30
Decimal Form:
x = −0.03
Step-by-step explanation:
5x(6x+28)=−23
Step 1: Simplify both sides of the equation.
30x2+140x=−23
Step 2: Subtract -23 from both sides.
30x2+140x−(−23)=−23−(−23)
30x2+140x+23=0
Step 3: Use quadratic formula with a=30, b=140, c=23.
x=−b±√b2−4ac/2a
x=−(140)±√(140)2−4(30)(23)/2(30)
x=−140±√16840/60
x=−7/3+1/30√4210 or x=−7/3+−1/30√4210
Answer:
-45
-26x+30
Step-by-step explanation:
So first you let's divide this equation into three parts.
Part one -9x(5x+4)
- Step one: you have to distribute the -9x to the numbers in the parentheses. That would leave us with a -9x*5x = -45
and -9x*4 = -36x - Step two: Put the answers together. That would leave us with -45
-36x.
Part two 10(x+3)
- Step one: you have to distribute the 10 to the numbers in the parentheses. That would leave us with a 10*x = 10x and 10*3 = 30
- Step two: Put the answers together. That would leave us with 10x+30
Part three solve
- Step one: combine and put together what you have solved for. That would leave us with a -45
-36x+ 10x+30 - Step two: combine like terms. The like terms here are -36x and 10x. When you combine them you would get -26x.
- Step three: Write the equation in standard form. Therefore the answer is -45
-26x+30.
Let me know if anything is confusing!
The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
the tangent line is the first derivative of the function</span></span></span><span>y′ = <span>b^2x/ a^2 y
hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1
</span></span></span></span>Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)
Step-by-step explanation:
Xj + Xk/2 = Xm
7 + Xk/2 = 1
to get rid of the bracket, multiply all two sides by the denominator.
2(7 + Xk/2) = 1(2)
7 + Xk = 2
Xk = 2 - 7
Xk = -5
Yj + Yk/2 = Ym
2 + Yk/2 = -2
to get rid of the bracket, multiply all two sides by the denominator.
2(2 + Yk/2) = -2(2)
2 + Yk = -4
Yk = -4 - 2
Yk = -6
Therefore the coordinates of point K is (-5,-6)