Answer:
b
Step-by-step explanation:
Make sure to not use the useless numbers on the slant. Also remember to divide by two at the end of calculating.
Step-by-step explanation:
Expression are problems with operations and terms, but no equal sign(s).
<u>Note: If a problem has an equal sign, it's an equation.</u>
*By eliminating the problems with equal signs, 12/4 =3 and 12 = 4 x 3 are incorrect.
12 + 4 - 3 and 12 - 4(3) are expressions, due to both problems not having an equal sign.
Answer:
(7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance.
Step-by-step explanation:
We have a large sample size n = 56 research cotton samples. Besides, and . A 95% large-sample CI for the true average percentage elongation is given by , i.e., or equivalently (7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance because we have a large sample.
Answer:
C.I. at 95% is as C.I.[0.7504 to 0.8162]
Step-by-step explanation:
Given:
Total number n=600
and Required No of students=x=470
To Find:
Determine a 95% confidence interval .
Solution:
Using normal distribution table for Z,
when 95 % C.I. Z=1.96
Now calculate ,
Population proportion,p=x/n
p=470/600
p=0.7833
Now calculate margin of error
MOE=Z*Sqrt[p(1-p)/n]
MOE=1.96*Sqrt[(0.7833*0.21667)/600]
=1.96*Sqrt(0.00028286)
=1.96*0.01681
=0.0329
So
The Boundaries will be as follows:
1)p-MOE
=0.7833-0.0329
=0.7504
2)p+MOE
=0.7833+0.0329
=0.8162