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motikmotik
3 years ago
5

During finals week, students arrive randomly at the help desk of the computer lab. There is only one technician due to budget cu

ts, and the time required to provide service varies from student to student. The average arrival rate is 15 students per hour, and the average service rate is 20 students per hour. Arrival rates have been found to follow the Poisson distribution, and the service times follow the exponential distribution. What is the average time spent waiting in line for each student?"
Business
1 answer:
KonstantinChe [14]3 years ago
5 0

Answer:

The average time spent waiting in line for each student is 2.25 students.

Explanation:

Use Lq with a single server formula.

λ = Avg arrival rate  = 15 std/hr

μ= Avg server rate (individual server capacity) = 20 std/hr

Μ = # of servers/line (identical capacities)

= λ^{2}/μ(μ- λ)

=15^{2} / 20(20-15)

= 225/100

=2.25 students.

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Suppose you invest every quarter, for 20 years, in an annuity that pays 5% interest, compounded quarterly. At the end of the 20
NikAS [45]

Answer:

Interest= $62983

Explanation:

Giving the following information:

Number of periods = 20*4 = 80 quarters

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8 0
4 years ago
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Answer:

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4 years ago
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Difference required from the bank = $12,000 ($17,000 - $5,000).

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