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sp2606 [1]
3 years ago
8

Find the limit of the function algebraically lim (x^2 -36 / x+6 ) x ->6

Mathematics
1 answer:
posledela3 years ago
3 0

9514 1404 393

Answer:

  0

Step-by-step explanation:

The function is defined everywhere except at x=-6. The limit value is the function value at that point.

  f(6) = (6^2 -36)/(6 +6) = 0/12 = 0

The limit of the function is 0 as x → 6.

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