Find the limit of the function algebraically lim (x^2 -36 / x+6 ) x ->6
1 answer:
9514 1404 393
Answer:
0
Step-by-step explanation:
The function is defined everywhere except at x=-6. The limit value is the function value at that point.
f(6) = (6^2 -36)/(6 +6) = 0/12 = 0
The limit of the function is 0 as x → 6.
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