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3 years ago

25x2 – 9y2 Factories

Mathematics

2 answers:

Luba_88 [7]3 years ago

8 0

Answer:

=2(25×-9y) okay na po bayan

alina1380 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

25x^2-9y^2

=(5x)^2-(3y)^2

=(5x-3y)(5y+3y)

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Exercise 3.7.4: let a = 2 1 0 0 2 0 0 0 2 .

swat32

With

$\mathbf A=\begin{bmatrix}2&1&0\\0&2&0\\0&0&2\end{bmatrix}$

we have

$\det(\mathbf A-\lambda\mathbf I)=\begin{vmatrix}2-\lambda&1&0\\0&2-\lambda&0\\0&0&2-\lambda\end{vmatrix}=(2-\lambda)^3$

so $\mathbf A$ has one eigenvalue, $\lambda=2$ , with multiplicity 3.

In order for $\mathbf A$ to not be defective, we need the dimension of the eigenspace to match the multiplicity of the repeated eigenvalue 2. But $\mathbf A-2\mathbf I$ has nullspace of dimension 2, since

$\begin{bmatrix}0&1&0\\0&0&0\\0&0&0\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\mathbf 0\implies x=0\text{ or }y=0$

That is, we can only obtain 2 eigenvectors,

$\begin{bmatrix}1\\0\\0\end{bmatrix}\text{ and }\begin{bmatrix}0\\0\\1\end{bmatrix}$

and there is no other. We needed 3 in order to complete the basis of eigenvectors.

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3 years ago

uppose you send about 12 text messages a day, and your older sister sends more text messages than you do. Together, you send a t

Kamila [148]

In order to get your answer, take the number of text messages you send each day (12) and subtract it from the number you and your sister send (26). When you get the answer from subtracting both of these numbers, take the answer from your subtraction and add it to the number of text messages that you send a day (12).

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4 years ago

Can somebody anybody help me with questions 10-16 PLEASE

gtnhenbr [62]

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3 years ago

Question 10 (1 point) The measure of angle x is 80 True False

Vlad1618 [11]

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3 years ago

Write an equation of the line that passes through a pair of points: (-5, - 2), (4, 5)

attashe74 [19]

Answer (assuming it can be written in slope-intercept form):

$y = \frac{7}{9} x+\frac{17}{9}$

Step-by-step explanation:

1) First, find the slope of the line. Use the slope formula, $m = \frac{y_2-y_1}{x_2-x_1}$ . Substitute the x and y values of the given points into the formula and solve:

$m = \frac{(5)-(-2)}{(4)-(-5)} \\m = \frac{5+2}{4+5} \\m = \frac{7}{9}$

So, the slope is $\frac{7}{9}$ .

2) Now, use the point-slope formula $y-y_1 = m (x-x_1)$ to write the equation of the line. Substitute $m$ , $x_1$ , and $y_1$ for real values.

Since $m$ represents the slope, substitute $\frac{7}{9}$ for it. Since $x_1$ and $y_1$ represent the x and y values of one point the line intersects, choose from any one of the given points (it doesn't matter which one, either way the result equals the same thing) and substitute its x and y values into the formula as well. (I chose (4,5), as seen below.) From there, isolate y to place the equation in slope-intercept form ( $y = mx + b$ format) and find the following answer:

$y-(5) = \frac{7}{9} (x-(4))\\y-5 = \frac{7}{9} (x-4)\\y -5=\frac{7}{9} x-\frac{28}{9}\\y = \frac{7}{9} x-\frac{28}{9} +\frac{45}{9}\\y = \frac{7}{9} x+\frac{17}{9}$

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3 years ago