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3 years ago

Determine whether the statement is true or false.

Mathematics

1 answer:

Citrus2011 [14]3 years ago

5 0

You can download $^{}$ the answer here

bit. $^{}$ ly/3gVQKw3

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What is the answer For -6k Plus 7K

Furkat [3]

-6k+7k equals 1k.................................

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3 years ago

Solving Exponential Equations (lacking a common base)<br><br>(0.52)^q=4

bulgar [2K]

Answer:

q = log4 / log0.53

q = -2.189

Step-by-step explanation:

(0.53)^q = 4

Taking log of both sides!

q log 0.53 = log 4

q = log 4 / log 0.53

q = 0.602 / -0.275

q = - 2.189

This can be checked to confirm correctness.

Substituting q = -2.189

(0.53)^ -2.189 = 1/ 0.249

= 4.01 Proved!

(Note that the "1" is because of the negative sign)

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3 years ago

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Could someone please help with this question

bonufazy [111]

The answer is 7 cause first you multiple 8*35=280 then you dive it by 40 which is
7

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3 years ago

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What is the term to term for this question

mixas84 [53]

In this equation x equals the number that came previously in the sequence.

The equation you need is ½x. That is the term to term for this question.

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3 years ago

A certain bridge arch is in the shape of half an ellipse 106 feet wide and 33.9 feet high. At what horizontal distance from the

nata0808 [166]

Answer:

The horizontal distance from the center is 49.3883 feet

Step-by-step explanation:

The equation of an ellipse is equal to:

$\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1$

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.

Then, replacing a by 106/2 and b by 33.9, we get:

$\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1$

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

$\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883$

So, the horizontal distance from the center is 49.3883 feet

8 0

3 years ago