Is the function even, odd, or neither
1 answer:
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Answer:
Option C.
Step-by-step explanation:
Let as consider parallel lines r and s are cut by transversal q. On line s where it intersects with line q, the uppercase left angle is 125 degrees and the bottom right angle is d degrees.
We need to find the value of d.
If a tranversal line intersect two parallel lines, then the alternate exterior angles are equal.
Uppercase left angle and bottom right angle are alternate exterior angles. So we can say that
d = 125°
Therefore, the correct option is C.
Answer:
The range is {12, 4, -6} ⇒ D
Step-by-step explanation:
<em>The range of the relation is the values of y corresponding to the values given for x which is the domain of the relation</em>
∵ The relation is 12x + 6y = 24
∵ The domain of the function is {-4, 0, 5}
→ That means x = -4, 0, 5, we need to find their corresponding values of y
∴ Substitute the values of x in the relation
∵ x = -4
∴ 12(-4) + 6y = 24
∴ -48 + 6y = 24
→ Add 48 to both sides
∴ -48 + 48 + 6y = 24 + 48
∴ 6y = 72
→ Divide both sides by 6 to find y
∴
∴ y = 12
∵ x = 0
∴ 12(0) + 6y = 24
∴ 0 + 6y = 24
∴ 6y = 24
→ Divide both sides by 6 to find y
∴
∴ y = 4
∵ x = 5
∴ 12(5) + 6y = 24
∴ 60 + 6y = 24
→ Subtract 60 from both sides
∴ 60 - 60 + 6y = 24 - 60
∴ 6y = -36
→ Divide both sides by 6 to find y
∴
∴ y = -6
∵ The range is the values of y which corresponding to the domain
∴ The range is {12, 4, -6}