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vivado [14]
3 years ago
13

Help ASAP please!!!!!!!!!​​

Mathematics
1 answer:
loris [4]3 years ago
3 0
The answer is: C.
I’m filling this so it can fill 20 characters DJDMD d c
D
Ddd
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What is the slope of the line that passes<br> through the points (-3,-2) and (2,-4)?
marta [7]

Answer:

Formula of the slope of the line

m=(y2-y1)/(x2-x1)

y2= -1, y1 = 4

x2=5, x1 = -2

m=(-1-4)/(5-(-2)) = -5/7

Answer is D. slope = -5/7

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A whole number is squared. The result is between 200 and 260. The number is between:
Anton [14]

Answer:

B

Step-by-step explanation:

b is correct

7 0
2 years ago
The function. In the graph is f(x) =
Tanya [424]

Answer:

x^3-2x^2-5x+6

Step-by-step explanation:

We have been given a graph of the function f(x).

Now we need to use that graph to find the equation of the graph and match with the correct choice from the give choices:

x^4-2x^2+5x+6

x^3-2x^2-5x+6

x^3-2x^2+5x+6

-x^4-2x^2+5x+6

We see that graph has end points in opposite direction then the degree of polynomial must be ODD.

Available degrees are 3 and 4. Degree 3 is odd so it is choice B or C.

Only x^3-2x^2-5x+6 satisfies the given points from graph.

Hence correct choice is x^3-2x^2-5x+6.

4 0
3 years ago
Find the midpoint of MN M=-24 N=1
LekaFEV [45]
Midpoint=12.5 let me know if this helps
4 0
2 years ago
(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
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