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e-lub [12.9K]
3 years ago
8

Katie’s goal is to read 6 books every 3 months. Based on this goal, how many months will it take Katie

Mathematics
1 answer:
Andrews [41]3 years ago
4 0

Answer:

12

Step-by-step explanation:

24/6=4 4x3=12

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Complete the ordered pairs (9,...), (..., 71) for the equation.<br> y= 10X-9
zaharov [31]

Answer:

(9, <u>81</u>) (<u>8</u>, 71)

Step-by-step explanation:

My explanation is in the picture. All I did was replace the known variable with the proper letter!

4 0
2 years ago
The equation (2x^2 - 1)(3x+2) = (2x²)(3x) + (2x²)(2) + (-1)(3x)+(-1)(2) is an example
Nookie1986 [14]

The method used is Distributive Property.

<h3>What is Distributive property?</h3>

The Distributive Property is an algebraic property that is used to multiply a single value and two or more values within a set of parenthesis.

Given:

(2x² - 1)(3x+2) = (2x²)(3x) + (2x²)(2) + (-1)(3x)+(-1)(2)

Here the property used is Distributive property.

Because distributive property in this way

a*(b+c)= a*b+ a*c

This is how a is being multiplied by with b and c.

Learn more about this Distributive property here:

brainly.com/question/4136433

#SPJ1

8 0
2 years ago
In cirle O, OE = 12, what is the length of the circle's radius<br><br>​
iren2701 [21]

Answer:

24?

Step-by-step explanation:

I'm not very good at math and I'm sorry if I'm wrong.

8 0
2 years ago
3x-7&gt;5<br> Find the solution, please show your work. Thank You!1
miskamm [114]
To find x just change the <span>> to a =
</span><span>3x-7=5
add 7
3x=12
then divide by 3
x=4

</span>

7 0
3 years ago
Read 2 more answers
Prove that an = 4^n + 2(-1)^nis the solution to
olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute a_n=4^n+2(-1)^n in the equation a_n=3a_{n-1}+4a_{n-2} the equality is true.

Let's substitute first in the right hand side:

3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})

Now we use the distributive laws. Also, note that (-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n} (this also works when the power is n-2).

=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}

=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}

=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n

then the sequence solves the recurrence relation.

4 0
3 years ago
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