All categories

3 years ago

X^3 + 5x^2 + 2x + 10 = 0

Mathematics

1 answer:

frosja888 [35]3 years ago

3 0

Let's solve your equation step-by-step.

x3+5x2+2x+10=0

Step 1: Factor left side of equation.

(x+5)(x2+2)=0

Step 2: Set factors equal to 0.

x+5=0 or x2+2=0

x=−5

Answer:

x=−5

You might be interested in

Ben starts walking along a path at 2 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the sam

devlian [24]

Answer:

25.7minutes

Step-by-step explanation:

D =r×t=2×1.5=3miles

A D=7÷2=3.5

7=1h. 3.5=30minutes.

3.5=30

0.5=x

3.5x÷3.5=15÷3.5

X=4.3

(3.5-0.5)=(30-4.3)

Hence it takes Amanda 25.7minutes to catch up with Ben.

5 0

3 years ago

1. Five more than a number is eight.

kolezko [41]

Answer

<u>3</u>, the number is 3

Step-by-step explanation:

work backwards, do 8-5 to get three. you can check to see if you're right by adding 5 to 3, which gives you 8.

4 0

3 years ago

A spa charges 40 dollars for a day pass and 20 dollars extra for treatments. What is the cost of going to the spa if you get 2 t

sergij07 [2.7K]

Answer:

$80 dollars.

Step-by-step explanation:

So you get charged $40 to get in and $20 extra for any treatment.

You get 2 treatments so that is $40.

$40+$40=$80 is your answer.

6 0

3 years ago

Express the product of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5Cf

Marta_Voda [28]

Answer:

Solution : 6 + 6i

Step-by-step explanation:

$-3\left[\cos \left(\frac{-\pi }{4})\right+i\sin \left(\frac{-\pi }{4}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi }{2}\right)\right]$

This is the expression we have to solve for. Now normally we could directly apply trivial identities and convert this into standard complex form, but as the expression is too large, it would be easier to convert into trigonometric form first ----- ( 1 )

( Multiply both expressions )

$-6\sqrt{2}\left[\cos \left(\frac{-\pi }{4}+\frac{-\pi \:\:\:}{2}\right)+i\sin \left(\frac{-\pi \:}{4}+\frac{-\pi \:\:}{2}\right)\right]$

( Simplify $\left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ for both $\cos \left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ and $i\sin \left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ )