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3 years ago

Write slope-intercept form an equation of the line passes through (-1,-1), (1,5)

1 answer:

3 0

Knowing that slope-intercept form is y=mx+b. mx being the slope and b being the y-intercept.

First, you will first find the slope, which is (y2-y1)/(x2-x1):
5-(-1) / 1-(-1) = Which becomes 6/2.
6/2 = 3. So the slope is 3x

Now when you plot the dots on a graph with a slope of 3 (basically 3/1 knowing that slope is rise over run) you will see that the point that intercepts on the y-axis is 2. So your y-intercept, or b in this equation, is 2.

I believe the slope-intercept form: y=3x+2

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State the slope and y-intercept of the graph of y + 2x = 3.

insens350 [35]

Answer:

y-intercept=(0, 3) slope=-2

hope this help

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the distance between the points (2,2) (5,5)

Ugo [173]

Answer: root18

Step-by-step explanation:

A (2,2) x1=2 y1=2

B (5,5) x2=5 y2=5

D(AB) = root [(x2-x1)^2 + (y2-y1)^2]

= root [(5-2)^2 + (5-2)^2]

= root [3^2 + 3^2]

= root (9+9)

D(AB)=root18

mark the brainliest plzz

3 0

3 years ago

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

3 years ago

Through: (3, 4), slope = -2

sineoko [7]

Answer:

y = -2x - 2

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Points: (3, 4)

Slope: -2

y = -2x + b

4 = -2 ( 3 ) + b

4 = -6 + b

b = -2

y = -2x - 2

8 0

3 years ago

Read 2 more answers

state if the triangles in each pair of similar. If so, State how you know that they are similar and complete the similarity stat

iragen [17]

Answer:

Similar, AA similarity, ΔAKL

Step-by-step explanation:

BC and KL are parallel. Therefore, ∠B and ∠K are alternate interior angles, and ∠C and ∠L are also alternate interior angles. Alternate interior angle are congruent, so by AA similarity, ΔABC ~ ΔAKL.

4 0

3 years ago