let's keep in mind that, in the II Quadrant, cosine is negative and sine, is positive.
cosine is adjacent/hypotenuse, however the hypotenuse is simply a radius unit, and thus is never negative, so in the -(2/3) the negative must be the numerator, -2.
Answer:
See below and attached picture
Step-by-step explanation:
a. To graph the equation set y = 0 and solve for t.
y = -16t² + 100
0 = -16t² + 100
100 = -16t²
6.25 = t²
+/- 2.5 = t
Mark the points (-2.5,0) and (2.5,0). Then mark the highest point at (0,100). Draw a curve or parabola to connect the points.
b. Domain is the set of t values. This is the time it's in the air. The graph shows it at height 100 at t = 0 and at height 0 at t = 2.5. The domain is [0, 2.5].
Range is the set of y values. This is the height of the object. The graph shows it at height 100 at the beginning and then falls to height 0. The range is [0,100].
c. The graph has the point (1,84). This means it was at height 84 feet at 1 second.
d. The graph has a point about (1.75, 50). This means at about 50 feet it was 1.75 seconds.
e. The shingle is at height 0 feet at 2.5 seconds when it crosses the x-axis.
