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3 years ago

15

It’s not 99/130 MARK BRAINLIEST

1 answer:

natali 33 [55]3 years ago

4 0

Answer:

31/130

Step-by-step explanation:

Since if u noticed that first they said liked the movie so of course the rest didn't liked it so we subtract 130 - 99 = 31 so we have a fraction 31/130

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Find the value of x in the triangle shown below.<br> 13<br> 5<br> х

katen-ka-za [31]

Answer:

x=12

Step-by-step explanation:

This is a right triangle, so the Pythagorean theorem can be used. The Pythagorean theorem states that $C^2=a^2+b^2$ where C is the hypotenuse and a and b are legs. In this question, we are given a and C. So, plugin 13 for C and 5 for a and solve for b. Once you rearrange the equation you get, $b=\sqrt{13^2-5^2}$ . Next, solve what is under the root to get, $b=\sqrt{144}$ . Finally, square root 144 for the final answer b=12.

3 0

3 years ago

Read 2 more answers

Please help me with this. (show work.)

BlackZzzverrR [31]

GCF: greatest common factor of any two (or more) numbers

Top left:

GCF of 24 and 60: 12

Top right:

GCF of 12 and 18: 6

Bottom left:

GCF of 18 and 42: 6

Right left:

GCF of 30 and 72: 6

5 0

3 years ago

Make this statement true

Nesterboy [21]

A is greater than -b

4 0

3 years ago

Find a formula for the inverse.

LUCKY_DIMON [66]

f(x) = 6x

To find the inverse, replace f(x) with Y:

y = 6x

Now switch the variables:

x = 6y

Solve for Y by dividing both sides by 6:

y = x/6

Now replace y with f^-1 (x):

f^-1 (x) = x/6

8 0

4 years ago

The 2004 presidential election exit polls from the critical state of Ohio provided the following results. There were 2020 respon

lord [1]

Answer: a) $0.490\leq p\leq0.582$

b) $0.501\leq p$

Step-by-step explanation:

Given : Sample size of respondents in the exit polls : n= 2020

Number of respondents voted for George Bush = 412

Sample proportion: $\hat{p}=\dfrac{412}{768}\approx0.536$

a) Critical value for 99% confidence level : $z_{\alpha/2}=2.576$

Confidence interval for proportion:-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$=0.536\pm (2.576)\sqrt{\dfrac{0.536(1-0.536)}{768}}\\\\=0.536\pm0.046\\\\=(0.490,\ 0.582)$

Hence, the 99% confidence interval for the proportion of college graduates in Ohio that voted for George Bush: $0.490\leq p\leq0.582$

b) Critical value for 95% confidence level : $z_{\alpha/2}=1.96$

Lower confidence bound for the proportion :

$\hat{p}- z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.536-(1.96)\sqrt{\dfrac{0.536(1-0.536)}{768}}\\\\=0.536-0.035=0.501$

Hence, a 95% lower confidence bound for the proportion of college graduates in Ohio that voted for George Bush : $0.501\leq p$

7 0

3 years ago

Read 2 more answers