we are given
equilateral triangle
we can see that triangle ACD is a right angled triangle
so, we can use Pythagoras theorem for this triangle
hypotenuse=AC
Adjacent=CD
opposite=AD=a
and
now, we can use Pythagoras theorem
and we get
now, we can plug values
now, we can solve for a
so, option-A..........Answer
Answer:
only G is even
it's obvious that g is even. g(x)= |x|
for ...
it's a quadratic equation with roots -1 and 4,
thus the equation will be
(if you have roots of a quadratic equation, the equation is
or
now, put the point (0,4)
so the equation is
now if you put
you get
which is not the same.
hence
I'm not 100% positive but I believe it would be the 14th person. 10+4=14. That's just my guess.
Ax^2 + bx + c
multiply the "a" and "c" coefficient
= ac
factor "ac" into a pair of numbers that adds to equal "b"
replace "bx" in the expression with factor pair
group terms and factor
* example problem:
2x^2 + 13x + 6
ac
2*6=12
factor pairs of 12
1*12 = 12
3*4=12
6*2=12
** The factor pair 1 and 12 add to make 13
replace 13x with (x+12x)
2x^2 + x + 12x + 6
group similar terms
(2x^2 + 12x) + (x + 6)
factor
2x(x + 6) + (x + 6)
The same parenthesis (x + 6) can be factored further by combining the outside multipliers 2x and 1
= (2x + 1)(x + 6)