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andreyandreev [35.5K]
3 years ago
13

Solve the system of equations algebraically.

Mathematics
1 answer:
Romashka [77]3 years ago
8 0
A should be the right answer because 4*5/4=5 + 5*2=10 and 5+10=15.
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Solve the inequality -2(z + 5) + 20 7 6.
Romashka-Z-Leto [24]

Answer:

z<2

Step-by-step explanation:

-2(z + 5) + 20 > 6

Subtract 20 from each side

-2(z + 5) + 20 -20 > 6-20

-2(z + 5) > -14

Divide each side by -2 remembering  to flip the inequality

-2/ -2(z + 5) < -14/-2

z+5 < 7

Subtract 5 from each side

z+5-5 < 7-5

z<2

8 0
3 years ago
Read 2 more answers
Please help solve this? (:
d1i1m1o1n [39]

Answer:

1 and Q

Step-by-step explanation:

The first and second one, as The angle can be whatever number or letter correlates with that one. R is a different point, and QRS isn't an actual angle.

Hope this helps :)

7 0
3 years ago
55% of 70 round to the nearest tenth
Verizon [17]
70 * 55/100=38.5

Enjoy
3 0
3 years ago
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Predict what the graph of the following quadratic function will look like. (If you have a graphing calculator, you can use it to
Alex17521 [72]

Answer:

u-shaped; y-intercept (0,6); symmetrical with respect to the y-axis

Step-by-step explanation:

Given that y = 2x² + 6

The graph would be the shape of that of a parabola. It can be u shaped or n shaped depending on the value of the coefficient of a comparing with the standard equation y = ax² + bx + c. If a > 0, it is u shape and if a < 0, it is n shape.

For this question, since a > 0 it would be u shaped and the intercept can be gotten by putting x = 0.

Therefore y = 0² + 6 = 0

The intercept is at (0,6) and is symmetrical with respect to the y-axis

3 0
3 years ago
The ratio of the perimeters of two similar triangles is 4:3. What are the areas of these triangles if the sum of their areas is
emmasim [6.3K]

Answer:

the areas of these triangles are 83.2cm² and 46.8cm²

Step-by-step explanation:

1. If the triangles are similar and the ratio of the perimeter ois 4:3, then the areas are in the following ratio:

4²:3²

 16:9                                                                      

2. The sum of their areas is 65 cm², then, you can calculate the area of the larger triangle as following:

130(16/16+9)

130(0.64)

=83.2cm²

3. The area of the smaller triangle is:

130(9/16+9)

130(0.36)

46.8cm²

<u>Hope this help</u>s

6 0
3 years ago
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