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Pachacha [2.7K]
3 years ago
9

!!!!!!!!!!!!!!!.....

Mathematics
2 answers:
N76 [4]3 years ago
6 0

Answer:

gagawin nyo po iyan sa papel

Goshia [24]3 years ago
3 0

Answer:

m\widehat {BDA} = 222\degree

Step-by-step explanation:

m\widehat {BDA} = 360\degree -(m\widehat {AC} +m\widehat {CB})

m\widehat {BDA} = 360\degree - (90\degree +48\degree)

m\widehat {BDA} = 360\degree - 138\degree

m\widehat {BDA} = 222\degree

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Help please i wanna get my assignments done by today so anyone willing to help please help
Blizzard [7]

Answer:

A - 4/25

Step-by-step explanation:

out of 50 trials Nadia got oraange 8 times

8 out of 50 = 8/50

this is the probability and can be simplified to 4/25

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3 years ago
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Can you plz help me with this math problem?
Sedaia [141]

Answer:

B

Step-by-step explanation:

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4 years ago
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Raheem's entire workout consisted of 15 minutes of warm-up exercises, 30 minutes of lifting weights,and 45 minutes on the treadm
Sindrei [870]

Answer:

b

Step-by-step explanation:

Time taken for the total workout = 15 + 30 + 45 = 90 minutes

Time taken for lifting weight : total time = 30 : 90

                                                                 = 1 : 3

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3 years ago
I bet you want Brainlest!! Click HERE!!!<br> Please help me!!!<br> BRaNiElsT!!!!!<br> Click!!!
Ilia_Sergeevich [38]

What? What's your question?

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3 years ago
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A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
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