Consider these specific values of x.
For example, if x=10, then <span>C(10)=16(10)+36,000=160+36,000=36,160 (say $)
and R(10)=18*10=180.
So if only 10 units are produced, the total cost is 36,160, while the revenue is only 180 (again, say $.)
If, for example, x=1000, then we can calculate
</span><span>C(1000)=16*1000+36,000=16,000+36,000=52,000
and
R(1000)=18*1000=18,000.
This suggests that with higher values of x, we can get to a particular point where the Cost and Revenue are the same. To find this point, we set the equation:
C(x)=R(x),
which gives us that particular x at which both </span>C(x) and R(x) give the same value.
Thus, we solve <span>16x+36,000=18x. Subtracting 16x from both sides 2x=36,000, then x = 36,000/2=18,000.
Answer: 18,000
</span>
Answer:
60 smaller vehicles had been washed
Step-by-step explanation:
1) Equation: 10y+5n=800, substitute the number of larger cars into the equation
2) 10x50 +5n=800
3)500+5n=800
4)5n=300
5)n=60
Answer:
k = 4
Step-by-step explanation:
Given,
when , P(x) is divided by (x - 1) , the remainder = 0
⇒ 
hence, k = 4
Answer:
<em>Q'</em> = (-4, -2)
<em>R' </em>= (4, -2)
<em>S'</em> = (4, 2)
<em>T'</em> = (-4, 2)
Step-by-step explanation:
First, we can create a matrix to scale this rectangle by putting all the x coordinates in the top row and all the y coordinates in the bottom row and multiply it by 4.
Our initial matrix to multiply:
![4\left[\begin{array}{cccc}-1&1&1&-1\\-2&-2&-1&-1\end{array}\right]](https://tex.z-dn.net/?f=4%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-1%261%261%26-1%5C%5C-2%26-2%26-1%26-1%5Cend%7Barray%7D%5Cright%5D)
Moved to the origin:
![4\left[\begin{array}{cccc}-1&1&1&-1\\-0.5&-0.5&0.5&0.5\end{array}\right]](https://tex.z-dn.net/?f=4%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-1%261%261%26-1%5C%5C-0.5%26-0.5%260.5%260.5%5Cend%7Barray%7D%5Cright%5D)
Multiplied by four:
![\left[\begin{array}{cccc}-4&4&4&-4\\-2&-2&2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-4%264%264%26-4%5C%5C-2%26-2%262%262%5Cend%7Barray%7D%5Cright%5D)
This gives us the points of
<em>Q'</em> = (-4, -2)
<em>R' </em>= (4, -2)
<em>S'</em> = (4, 2)
<em>T'</em> = (-4, 2)
which are our answers.
