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Marrrta [24]
3 years ago
8

Can somebody help me?????

Mathematics
2 answers:
natta225 [31]3 years ago
6 0

Answer:

1/2 = 3/6

Step-by-step explanation:

.................

Damm [24]3 years ago
5 0

Hai!

Your answer would be 3!

Brainliest maybe?

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Find an equation of the line that is perpendicular to the graph of 2x+5y=5 and contains the point of intersection of the graphs
gavmur [86]

Answer:

  5(x+1) -2(y-3) = 0

Step-by-step explanation:

For a given line ax+by=c and point (h, k), a perpendicular line through the point can be written as ...

  b(x-h) -a(y-k) = 0

A graphing calculator shows the point of intersection of the graphs of the two lines to be (x, y) = (-1, 3), so the line perpendicular to 2x+5y=5 through that point can be written ...

  5(x+1) -2(y-3) = 0

_____

In the attached graph, the requested line is shown in black.

3 0
3 years ago
Simplify (-2 + 3i) + 2(5 + 6i). Enter your answer in the form a + bi.
Reptile [31]

We will have the following:

(-2+3i)+2(5+6i)=-2+3i+10+12i

=(10-2)+(3i+12i)=8+15i

So, the solution would be:

8+15i

3 0
1 year ago
BRAINIEST TO WHOEVER RIGHT
adoni [48]

Answer:

i know b only Sorry hope this helps tho

Step-by-step explanation:

its 4 because each space is 25% no matter how big or small it is. so if you land on -9 to -5 thats 25% and to -2 thats another 25% total 50% its asking for 75% so you go one more which lands on 4 making it 75%

5 0
3 years ago
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Sally is analyzing a circle, y2 + x2 = 9, and a linear function g(x). Will they intersect?
Mamont248 [21]
This ones kinda hard I'm not really sure, but looking at the table, when f(x) = 1, g(x) = 1. So therefore it is yes, and Im guessing you know the negative and positive x coordinates/zero thing, so I think you should be correct. Sorry if this is wrong, not too sure, but hopefully it gives you a better idea.
4 0
3 years ago
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Chelsea wants to determine the number of people in her school who read news reports on the Internet daily. She asks five people
elena-s [515]

Answer:

- increase the sample size

- choose students from different grade levels

- choose every fourth student in all language arts classes

Your welcome :]

3 0
3 years ago
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