Answer:
Either word or I would suggest using google docs and word and compare.
Explanation:
You can set up a resume in word.
Data visualization
Data visualization is a good starting point for data mining. There are several approaches to data mining that supports smart decisions. Data visualization places data in a visual context. It extracts the data in a clear and understandable way without any form of reading or writing. Results are displayed in the form of pie charts, graphs, and any other statistical representation. Such multidimensional views of data aid in developing a preliminary understanding of the trends that are hidden in the data set.
When u are in the mouse properties window you can change the speed in which your pointer moves, change the speed of your double click on the mouse, change the look of the pointer make the pointer automatically move to default button in a dialog box have the pointer hide while you are typing. and change the number of lines that the scroll wheel will move when using it. there's actually a lot of optoons available in the mouse properties window. HOPE I WAS HELPFULL
Answer:
class studentType: public personType
{
public:
virtual void print() = 0;
virtual void calculateGPA() = 0;
void setID(long id) {
studentId = id;
}
void setCourses(const string c[], int noOfC) {
noOfCourses = noOfC;
for (int i=0; i<noOfCourses; i++) {
courses[i] = c[i];
}
}
void setGrades(const char cG[], int noOfC) {
noOfCourses = noOfC;
for (int i=0; i<noOfCourses; i++) {
coursesGrade[i] = cG[i];
}
}
long getID() {
return studentId;
}
string* getCourses() {
return courses;
}
char* getGrades() {
return coursesGrade;
}
studentType(string fName = "", string lastName = "",
long id = 0, string c[] = NULL, char cG[] = NULL, int noOfC = 0);
private:
long studentId;
string courses[6];
char coursesGrade[6];
int noOfCourses;
};
Explanation:
Code rewritten
Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string str)
{
char a,b;
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
a=tolower(str[i]);//Converting both first characters to lowercase..
b=tolower(str[length-1-i]);
if (b != a )
return false;
}
return true;
}
int main() {
string t1;
cin>>t1;
if(isPalindrome(t1))
cout<<"The string is Palindrome"<<endl;
else
cout<<"The string is not Palindrome"<<endl;
return 0;
}
Output:-
Enter the string
madam
The string is Palindrome
Enter the string
abba
The string is Palindrome
Enter the string
22
The string is Palindrome
Enter the string
67876
The string is Palindrome
Enter the string
444244
The string is not Palindrome
Explanation:
To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.
