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nydimaria [60]
3 years ago
7

What factoring method do you use to factor u²+70

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer: 3) Not factorable

We cannot use the difference of squares method because we don't have a subtraction going on (ie "difference") and we don't have two perfect squares. The value 70 is not a perfect square.

We cannot factor out a GCF since the GCF here is 1, and that doesn't really affect things. Choice 4 is also not applicable because we don't have a trinomial. A trinomial has three terms.

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Step-by-step explanation:

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A ticket service is selling tickets to a concert. An order of 4 tickets has a price of $63 and an order of 6 tickets has a price
Valentin [98]

Answer:

<u>x = Number of tickets for the concert</u>

<u>y = Price of the order of x tickets</u>

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Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Order of 4 tickets has a price of $63

Order of 6 tickets has a price of $92

2. Write an equation to find the price of any amount of tickets.

Let's find out the price of a ticket to understand if there's a service fee and how much is it, this way:

Price of a ticket = (Order of 6 tickets - Order of 4 tickets)/2

Price of a ticket = (92 - 63)/2

Price of a ticket = 29/2 = 14.50

If a ticket costs $ 14.50, 4 tickets will cost $ 58 and 6 tickets will cost $ 87, therefore there is a service or delivery fee of $ 5.

Order of 4 tickets - Price of 4 tickets = Service or delivery fee

Replacing, we have:

63 - 58 = 5

Order of 6 tickets - Price of 6 tickets = Service or delivery fee

Replacing, we have:

92 - 87 = 5

Now, we can write the equation to find the price of an order of any amount of tickets, this way:

<u>x = Number of tickets for the concert</u>

<u>y = Price of the order of x tickets</u>

<u>y = 14.5x + 5</u>

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What are the roots of 27x^3=8
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\bf 27x^3=8\implies x^3=\cfrac{8}{27}\implies x = \sqrt[3]{\cfrac{8}{27}}\implies x = \sqrt[3]{\cfrac{2^3}{3^3}} \\\\\\ x = \cfrac{\sqrt[3]{2^3}}{\sqrt[3]{3^3}}\implies x=\cfrac{2}{3}

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3 years ago
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