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Basile [38]
2 years ago
10

PLEASE Which number sentence is true?

Mathematics
1 answer:
ANEK [815]2 years ago
3 0

Answer:

D) -21.3 > -32.1 answer true .

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What is the equation of this graphed line?
cestrela7 [59]
First we find the slope by using the slope formula : (y2 - y1) / (x2 - x1)

slope = (y2 - y1) / (x2 - x1)
(0,7)....x1 = 0 and y1 = 7
(8,-2)...x2 = 8 and y2 = -2
now sub...pay attention to ur signs
slope = (-2 - 7) / (8 - 0) = -9/8

now we use y = mx + b
slope(m) = -9/8
u can use either of ur points...(0,7)...x = 0 and y = 7
now sub into ur formula and find b, the y int
7 = -9/8(0) + b
7 = b
so ur equation is : y = -9/8x + 7 <==
5 0
3 years ago
The left line I need help please
fgiga [73]
Try using Photomath for some it’s easy and faster than waiting for people to respond on here i can help u when I’m done w this test with the left side if ur still stuck
5 0
3 years ago
Given GH with endpoints (-7,3) andH (7. - 11), what are the coordinates of the<br> mielpoint of GH?
Y_Kistochka [10]

Answer:

Midpoint is (0, -4)

Step-by-step explanation:

x-coordinate of midpoint = (-7 + 7)/2 = 0/2 = 0

y-coordinate of midpoint = (3 - 11)/2 = -8/2 = -4

Midpoint is (0, -4)

8 0
3 years ago
Read 2 more answers
Thx in advance for the help
lubasha [3.4K]

Answer: x\geq 13

Step-by-step explanation:

Given

The inequality is  2x-7\geq 19

adding both side 7

2x-7+7\geq 19+7\\2x\geq 26

Multiply both sides by \frac{1}{2}

\dfrac{1}{2}\times 2x\geq 26\times \dfrac{1}{2}\\\\x\geq 13

the shaded region in the figure indicates the solution set.

6 0
3 years ago
A polynomial function has a zero at 4 (multiplicity 3) and 0 (multiplicity 1). Write a function in standard form that can repres
VLD [36.1K]

Answer:

(x^4) - 64x

Step-by-step explanation:

zeros at 4 and 0 are the roots so can be factor as x*(x-4) and the multiplicity tels to what power you have to raise those factors

x^{1} *(x-4)^{3} becuase multiplicity of 1 for root at 0, and multiplicity of 3 at root 4

now to write this in standard form

x*(x-4)^{3} = \\x*(x-4)(x^{2} +4x+16)= \\(x^{2} -4x)(x^{2} +4x+16) = \\x^{4} +4x^{3} +16x^{2} -4x^{3} -16x^{2} -64x = \\x^{4} -64x

8 0
2 years ago
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