All categories

2 years ago

HELP NEEDED ASAP I WILL GIVE BRAINLIEST TO WHOEVER GETS CORRECT

Mathematics

2 answers:

jolli1 [7]2 years ago

8 0

Answer:

(10, 5)

Step-by-step explanation:

Scilla [17]2 years ago

3 0

Answer:

Step-by-step explanation:

10+5=15

-10+5=-5

give brainliest if right.

You might be interested in

Which is equal to cos47°?

Murrr4er [49]

Which of these is equal to cos 47°?

a. cos 43°

b. sin 43°

c. tan 43°

d. cos 133°

B.....

cos (47°)= sin (90°-47°)=sin (43°) [complementary angles]

Answer B

7 0

3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

Sam has 4 gallons of juice. Each glass holds 1/5 of a gallon . How many glasses can he fill

Softa [21]

Answer:

Step-by-step explanation:

Divide 4 by 1/5 in decimal form, 1/5 in decimal form is 0.20. You can get the decimal form by dividing 1 by 5.

So 4/0.20 = 20.

6 0

3 years ago

Together Pam, Dan and Sam have 31.00. How many dollars does Sam have if Dan has 3.00 less than Pam, and Sam has 1.00 more than p

shepuryov [24]

Answer:

16.00 dollars

Step-by-step explanation:

7 0

3 years ago

Could you guys help me pwease

WINSTONCH [101]

Answer:

Step-by-step explanation:

The answer is D. Hope that helps, so sorry if I'm wrong

3 0

2 years ago

Read 2 more answers