Answer:
12 unit²
Step-by-step explanation:
area ΔAMC = 1/2 CM x AH' = 1/4 BC x AH'
area ΔABM = 1/2 BM x AH' = 1/4 BC x AH'
area ΔAMC = area ΔABM
for the same calculation, we can prove
area ΔACN = area ΔDCN
area ΔAMC + area ΔACN = 6
area ΔABM + area ΔDCN = 6
ABCD = area ΔAMC + area ΔACN + area ΔABM + area ΔDCN = 6 = 6 = 12
Answer:
P(25 < x < 37) = 0.77
Step-by-step explanation:
Given - If a Variable has a normal distribution with mean 30 and standard deviation 5
To find - find the probability that the variable will be between 25 and 37.
Proof -
Given that,
Mean, μ = 30
S.D, σ = 5
Now,
~ N(0,1)
Now,
P(25 < x < 37)
=
= P(1 < z < 1.4)
= P(z < 1.4) - P(z < -1)
= 0.9192 - 0.1587
= 0.7605
≈ 0.77
∴ we get
P(25 < x < 37) = 0.77