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Levart [38]
3 years ago
12

CAN SOMEONE PLEASE HELP ME I’M STRUGGLING PLEASE I NEED HELP NO ONE IS HELPING ME WHYYY

Mathematics
1 answer:
Simora [160]3 years ago
5 0
22.5 is the answer i think
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Complete parts (a) and (b) using the probability distribution below.
katen-ka-za [31]
Μ = (0×0.026) + (1×0.072) +(2×0.152) + (3×0.303) + (4×0.215) + (5×0.164) + (6×0.066) 
μ = 0 + 0.072 + 0.304 + 0.909 + 0.86 + 0.82 + 0.396
μ = 3.361 ≈ 3.4

We need the value of ∑X² to work out the variance
∑X² = (0²×0.026) + (1²×0.072) + (2²×0.152) + (3²×0.303) + (4²×0.215) + (5²×0.164) + (6²×0.066)
∑X² = 0+0.072+0.608+2.727+3.44+4.1+2.376
∑X² = 13.323

Variance = ∑X² - μ²
Variance  = 13.323 - (3.4)² = 1.763 ≈ 2

Standard Deviation = √Variance = √1.8 = 1.3416... ≈ 1.4

The correct answer related to the value of mean and standard deviation is the option D
<span>
An employee works an average of 3.4 overtime hours per week with a standard deviation of approximately 1.4 hours.</span>
7 0
3 years ago
Sub to bionic pleasssssse
BlackZzzverrR [31]
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4 0
3 years ago
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Masja [62]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Which statement is NOT true about the ratio of the leg lengths of increment ΔLRM and increment ΔJSK?
Alona [7]
Given the similar triangles, it can always be noted that similarity can be derived from the proportionality of the leg lengths, however it is not true the the ratio of the proportion of the leg lengths is equal to the slope of the triangles. Thus the false statement is:
A]  <span>The slope of the hypotenuse is represented by the ratio of the leg lengths.</span>
7 0
3 years ago
If angle 4 is 52.7, what are the measures of angles 1,2, and 3? ​
shusha [124]

Answer:

  1. 127.3
  2. 52.7
  3. 127.3
  4. 52.7

Step-by-step explanation:

Since we know the angle measure of angle 4, we already know that angle 2 will have the same measure according to do the vertical angle theorem. Now to find angles 1 and 3, we can make an equation and solve for x (supplementary angles).

52.7 + x = 180

x = 127.3

Best of Luck!

6 0
2 years ago
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