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bezimeni [28]
3 years ago
8

How do you solve this equation 9/4 Divided by -3/4? Anything will help Thanks ^w^

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

you would have to multiply and Keep change flip keep the 9/4 change the division to miltiplication and flip -3/4 to 4/-3 then u slove

9/4 * 4/-3

Step-by-step explanation:

Karo-lina-s [1.5K]3 years ago
8 0
First you have to take the reciprocal of the -3/4. This means you flip it. Then since you flipped it, the division also changes to multiplication.
Now your equation is 9/4 x -4/3.
If you multiply that you get -32/12 as your answer.
That simplifies to -8/3 as your final answer

Hope this helps!
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Match the following equation to the correct situation.
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Answer:

The equation given in the question matches the situation C.

Step-by-step explanation:

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B. The amount is given to a charity after saving 15% of p. That means if p is the amount of charity, then there were a savings of 15% of p.

Therefore, the total charity payment after savings = p - 15% of p = p - \frac{15p}{100} = p - 0.15p = 0.85p

C. The amount that Sandy paid for a shirt with 15% tax on p.

Therefore, if the price of a shirt is p, then total payment of Sandy after tax is = p + 15% of p = (p + \frac{15p}{100}) = p + 0.15p = 1.15p

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8 0
3 years ago
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
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2 years ago
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6 0
2 years ago
Read 2 more answers
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aev [14]
Step by step I’m not sure sorry dog
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